Problem 2- 51 In Figure 13, in which fluid will a pressure of 700 kPa first be achieved? Ans: glycerin Po = 90 kPa ethyl alcohol p = 773.3 kg/m2 60 m oil p = 899.6 kg/m 10 m water p 979 kg/m glycerin p 1236 kg/m 5 m 5 m
Problem 2- 51 In Figure 13, in which fluid will a pressure of 700 kPa first be achieved? Ans: glycerin Po = 90 kPa ethyl alcohol p = 773.3 kg/m2 60 m oil p = 899.6 kg/m 10 m water p 979 kg/m glycerin p 1236 kg/m 5 m 5 m
Chapter2: Loads On Structures
Section: Chapter Questions
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![Problem 2- 51
* In Figure 13, in which fluid will a pressure of 700 kPa first be achieved?
Ans: glycerin
Po = 90 kPa
ethyl alcohol
p= 773.3 kg/m2
60 m
oil
10 m
p 899.6 kg/m
water
p = 979 kg/m
glycerin
p = 1236 kg/m
5 m
5 m
E E](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd7246146-df84-418a-875e-3b5a73c03d39%2Fc5ba12b0-3247-4601-b39e-0d20b4b9822f%2Fsiomcbn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 2- 51
* In Figure 13, in which fluid will a pressure of 700 kPa first be achieved?
Ans: glycerin
Po = 90 kPa
ethyl alcohol
p= 773.3 kg/m2
60 m
oil
10 m
p 899.6 kg/m
water
p = 979 kg/m
glycerin
p = 1236 kg/m
5 m
5 m
E E
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