Answer Problem 2 8:57CE497_R3 FEShow complete solution and draw if necessary. Correct answer with incorrect or incompletesolution will not be given points.Problem 1 (20pts): A simply supported rectangular wooden beam has a span of 6 m. and carries atotal uniform load of 25 kN/m including its own weight. The beam is made up of 50% stress gradeAgoho. (Refer to table for the allowable stresses)a. If the beam width is 200mm and beam depth is 400 mm. What is the maximum flexural stressof the beam? Is it safe?b. What should be the area of the beam that will not exceed the allowable shearing stress?Species1. High Strength GroupAgohoLiusinMalabayabasManggachapuiMolaveNarigSasalitYakal2"Table TMBR-2: Properties of Philippine Wood at 50% GradeBending andModulus ofTension Parallel Elasticity inCompressionParallel toto GrainBendingGrainOMPa16.4015.6017.9016.1015.0013.6019.6015.30GPaO5.145.855.196.024.095.206.083.11MPa9.069.769.9010.09.608.5913-59.553/4-in.-diameter boltsCompressionPerpendicularto GrainMPaOASTMDesignation5G 533.692.695-443-773-963.116.403-92Problem 2 (10pts): Compute for the net area of the plate with staggered fasteners considering thefailure line shown in the figure below.−| 2"″ |¶ 3″ ►¶ 3"″ ►◄ 3″ |¶ 3″ ►¶ 3″ ►| — |Commit to the LORD whatever you do, and your plans will succeed.Proverbs 16:3God bless. ⒸShear Parallelto GrainMPa1.841.651.891.741.801.632.12Fy FuYield TensileStress Stress(ksi) (ksi)1.55-PL ¾ x12Problem 3 (20pts): Compute the nominal compressive strength of the member shown. Use thetheoretical value for K (Refer to table C-A-7.1).

Give data: Width of plate, b=12 in Thickness of plate, t=58 in Bolt diameter, db=34 in The net area…

Problem 2 (10pts): Compute for the net area of the plate with staggered fasteners considering the failure line shown in the figure below. ►| 2″ |◄ 3″′ ►le 3″′ ►¶ 3"″ ► ¶ 3″ ►¶ 3″►le—–— 2" + 4 이하 2" O O O 3/4-in.-diameter bolts -PL ¾ x12

Problem 2 (10pts): Compute for the net area of the plate with staggered fasteners considering the failure line shown in the figure below. ►| 2″ |◄ 3″′ ►le 3″′ ►¶ 3"″ ► ¶ 3″ ►¶ 3″►le—–— 2" + 4 이하 2" O O O 3/4-in.-diameter bolts -PL ¾ x12

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A simply supported beam has a maximum moment equal to 20 KN.m. The beam has a width of 200 mm and a depth of 250 mm and is made up of 80% grade Narra. What is the actual bending stress of the beam in MPa? Blank 1 (use two decimal places, no need for unit)\\ with complete solution
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A) Determine the shape factor and the Fully Plastic Moment (Mp) for the shaded symmetrical hollow rectangular beam section shown below. Assume the yield stress Oy =275 N/mm². B) If two plates of width 250 mm and thickness equal to 't' mm is connected (fabricated) at top and bottom (one plate on each side) for the given section, then what is the improvement in the fully plastic moment(Mp) of the section. C) If this revised fabricated section is now rotated by 90 degrees, what is its effect on the shape factor of the section? 200 mm. 50 m 100 ma 400 t- 10mm Note Take the value the 't' as equal to the last two digits of your studentid. If the last two digits are zero then take timm
A) Determine the shape factor and the Fully Plastic Moment (Mp) for the shaded symmetrical hollow rectangular beam section shown below. Assume the yield stress Oy =275 N/mm². B) If two plates of width 250 mm and thickness equal to 't' mm is connected (fabricated) at top and bottom (one plate on each side) for the given section, then what is the improvement in the fully plastic moment(Mp) of the section. C) If this revised fabricated section is now rotated by 90 degrees, what is its effect on the shape factor of the section? 200 mm. -50 m 100 mm t- 10 400 Note Take the value the 't' as equal to-the last two digits of your student-id. If the-last two digits are zero then take taimm
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Title: Design of Beam in Flexure (WSD Method) PROBLEM: Design the beam to resist the loads shown. Take fc = 9 MPa, fs = 124 MPa, n = 11, bar diameter = 20 mm. Take b = d/2. Use WSD method. As (Gomm 20 KN lo Ka/m 8 KN/m 3m
60 mm 150 mm 60 mm 300 mm 600 III 60 mm 150 m