Problem 18.03: In an equilateral triangular-shaped parcel, the height (altitude) of the triangle is 5 ft. less than its side length. The side length (ft.) of the triangle is most nearly equal to: A. B. C. D. 10 ft. 20 ft. 30 ft. 40 ft.
Problem 18.03: In an equilateral triangular-shaped parcel, the height (altitude) of the triangle is 5 ft. less than its side length. The side length (ft.) of the triangle is most nearly equal to: A. B. C. D. 10 ft. 20 ft. 30 ft. 40 ft.
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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
Transcribed Image Text:Problem 18.03: In an equilateral triangular-shaped parcel,
the height (altitude) of the triangle is 5 ft. less than its side
length. The side length (ft.) of the triangle is most nearly
equal to:
A.
B.
C.
D.
10 ft.
20 ft.
30 ft.
40 ft.
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