Problem 16The assembly shown supports a distributed load of w = 0.8 kip/ft. The pins at A and B are 0.4" indiameter and the rod has a ½" diameter. The yield strength of the pin in shear is 25 ksi and therod's tensile yield strength is 38 ksi.a.b. Calculate the factor of safety with respect toyielding in the rod.C.Calculate the force in rod AB. Don't forget to drawa FBD!e.Calculate the factor of safety with respect toyielding for the pins.d. What value would you report as the final factorof safety for the structure? Explain youranswer.Pin at B3 ftB4 ftPin at A2 ftIf the rod is made of structural steel (E = 29,000 ksi, v = 0.33), calculate the final diameter of rod AB.W

Answered: Problem 16 The assembly shown supports…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Concept explainers

Question

Problem 16
The assembly shown supports a distributed load of w = 0.8 kip/ft. The pins at A and B are 0.4" in
diameter and the rod has a ½" diameter. The yield strength of the pin in shear is 25 ksi and the
rod's tensile yield strength is 38 ksi.
a.
b. Calculate the factor of safety with respect to
yielding in the rod.
C.
Calculate the force in rod AB. Don't forget to draw
a FBD!
e.
Calculate the factor of safety with respect to
yielding for the pins.
d. What value would you report as the final factor
of safety for the structure? Explain your
answer.
Pin at B
3 ft
B
4 ft
Pin at A
2 ft
If the rod is made of structural steel (E = 29,000 ksi, v = 0.33), calculate the final diameter of rod AB.
W

Expert Solution

Step 1 Given

“Since you have posted a question with multiple sub-parts, we will provide the solution only to the first three sub-parts as per our Q&A guidelines. Please repost the remaining sub parts separately.”

The yield strength of the pin is $τ_{y p} = 25 k s i$

The yield strength of the rod is $σ_{y r} = 38 k s i$

The diameter of the pins is $d = 0.4 i n$

The diameter of the rod is $D = 0.5 i n$

The uniformly distributed load is $w = 0.8 k i p / f t$

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions