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Problem 15. A copper alloy wire of 1.5 mm diameter and 30 m long is hanging reely from a tower. When will be its elongation due to self weight? Take specific of the copper and its modulus of elasticity as 89.2 kN/m³and 90 Gpa respectively.

Problem 15. A copper alloy wire of 1.5 mm diameter and 30 m long is hanging reely from a tower. When will be its elongation due to self weight? Take specific of the copper and its modulus of elasticity as 89.2 kN/m³and 90 Gpa respectively.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Given data: Cross sectional area, A 2 mm2; Weight, W = 12 N; Extension, 8 = 0.6 mm %3D 3 Modulus of elasticity, E 150 Gpa = 150×10° N/mm´ %3D To find: Maximum length or wire Solution: Let, l maximum length of the wire, Extension of the wire under its own %3D weight, We 12xl 0.6 0.6 = 0.02x10-3l; l = 30000mm 30m %3D %3D %3D 2AE 2x2x(150x10) 0.02x103 Result: Maximum length of wire = 30 m Problem 15. A copper alloy wire of 1.5 mm diameter and 30 m long is hanging freely from a tower. When will be its elongation due to self weight? Take specific of the copper and its modulus of elasticity as 89.2 kN/m³and 90 Gpa respectively. Given data: 30x10 89.2 kN/m°= 89.2×10° kN/mm = 89.2×10°N/mm³ 90 Gpa = 90 x 10° N/mm². Diameter, d 1.5 mm; Length, L =30m mm 3 -6 Specific weight, w = Modulus of elasticity, E To find: Elongation of the wire. 8 x(d)* 품지(1.5)°-1 Solution: Cross-sectional area of the wire, A = %3D
Transcribed Image Text:Given data: Cross sectional area, A 2 mm2; Weight, W = 12 N; Extension, 8 = 0.6 mm %3D 3 Modulus of elasticity, E 150 Gpa = 150×10° N/mm´ %3D To find: Maximum length or wire Solution: Let, l maximum length of the wire, Extension of the wire under its own %3D weight, We 12xl 0.6 0.6 = 0.02x10-3l; l = 30000mm 30m %3D %3D %3D 2AE 2x2x(150x10) 0.02x103 Result: Maximum length of wire = 30 m Problem 15. A copper alloy wire of 1.5 mm diameter and 30 m long is hanging freely from a tower. When will be its elongation due to self weight? Take specific of the copper and its modulus of elasticity as 89.2 kN/m³and 90 Gpa respectively. Given data: 30x10 89.2 kN/m°= 89.2×10° kN/mm = 89.2×10°N/mm³ 90 Gpa = 90 x 10° N/mm². Diameter, d 1.5 mm; Length, L =30m mm 3 -6 Specific weight, w = Modulus of elasticity, E To find: Elongation of the wire. 8 x(d)* 품지(1.5)°-1 Solution: Cross-sectional area of the wire, A = %3D
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