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Problem #15: Fill in the blanks below to show how you would find the zeros of the equation: J(x)=x + 4x + 8 1. The value of the discriminant in this equation is equal to the square root of this becomes± And after simplifying, 2. After subbing into the Quadratic Formula, the numerator would be 3. After subbing into the Quadratnt Formula, the denominator would be 4. Finally, after simplifying our two solutions to the equation would be and

Problem #15: Fill in the blanks below to show how you would find the zeros of the equation: J(x)=x + 4x + 8 1. The value of the discriminant in this equation is equal to the square root of this becomes± And after simplifying, 2. After subbing into the Quadratic Formula, the numerator would be 3. After subbing into the Quadratnt Formula, the denominator would be 4. Finally, after simplifying our two solutions to the equation would be and

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem #15:** Fill in the blanks below to show how you would find the zeros of the equation: \( f(x) = x^2 + 4x + 8 \) 1. The value of the discriminant in this equation is equal to the square root of _______. And after simplifying, this becomes \( \pm \) _______. 2. After subbing into the Quadratic Formula, the numerator would be _______ \( \pm \) _______. 3. After subbing into the Quadratic Formula, the denominator would be _______. 4. Finally, after simplifying our two solutions to the equation would be _______ and _______.
Transcribed Image Text:**Problem #15:** Fill in the blanks below to show how you would find the zeros of the equation: \( f(x) = x^2 + 4x + 8 \) 1. The value of the discriminant in this equation is equal to the square root of _______. And after simplifying, this becomes \( \pm \) _______. 2. After subbing into the Quadratic Formula, the numerator would be _______ \( \pm \) _______. 3. After subbing into the Quadratic Formula, the denominator would be _______. 4. Finally, after simplifying our two solutions to the equation would be _______ and _______.
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