Problem 14.4. Use Taylor polynomials in order to approximate the functions and calculate the following limits: sin(8x) lim x→0 sin(7x) (14.20) sin(x) – x lim - (14.21) In(1+ x) lim x→0 e5x (14.22) 1 1

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hi, I hope you are doing well. I have some questions in the attached JPG file where I need to use Taylor polynomials to find the limit.

**Problem 14.4.** Use Taylor polynomials in order to approximate the functions and calculate the following limits:

\( (14.20) \) 
\[
\lim_{x \to 0} \frac{\sin(8x)}{\sin(7x)}
\]

\( (14.21) \) 
\[
\lim_{x \to 0} \frac{\sin(x) - x}{x^5}
\]

\( (14.22) \) 
\[
\lim_{x \to 0} \frac{\ln(1 + x)}{e^{5x} - 1}
\]

\( (14.23) \) 
\[
\lim_{x \to 0} \frac{4^x - 1}{7x - 1}
\]

\( (14.24) \) 
\[
\lim_{x \to 0} \frac{\ln(1 + x) - x}{1 - x^2 \cos(x)}
\]
Transcribed Image Text:**Problem 14.4.** Use Taylor polynomials in order to approximate the functions and calculate the following limits: \( (14.20) \) \[ \lim_{x \to 0} \frac{\sin(8x)}{\sin(7x)} \] \( (14.21) \) \[ \lim_{x \to 0} \frac{\sin(x) - x}{x^5} \] \( (14.22) \) \[ \lim_{x \to 0} \frac{\ln(1 + x)}{e^{5x} - 1} \] \( (14.23) \) \[ \lim_{x \to 0} \frac{4^x - 1}{7x - 1} \] \( (14.24) \) \[ \lim_{x \to 0} \frac{\ln(1 + x) - x}{1 - x^2 \cos(x)} \]
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