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Problem 14. [Projectile Motion/Kinematics 2D] An airplane is flying with a velocity of 240 m/s at an angle of 30.0° with the horizontal, see diagram below. When the altitude of the plane is 2.4 km, a flare is released from the plane. The flare hits the target on the ground. (a) What is the angle 0? K00 Find V, 30.0° = 240 m/s Fuel tby 3 Path of flare 2.4 km Target Line of sight Line

Problem 14. [Projectile Motion/Kinematics 2D] An airplane is flying with a velocity of 240 m/s at an angle of 30.0° with the horizontal, see diagram below. When the altitude of the plane is 2.4 km, a flare is released from the plane. The flare hits the target on the ground. (a) What is the angle 0? K00 Find V, 30.0° = 240 m/s Fuel tby 3 Path of flare 2.4 km Target Line of sight Line

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem 14: Projectile Motion/Kinematics 2D** **Scenario:** An airplane is flying with a velocity of 240 m/s at an angle of 30.0° with the horizontal. When the altitude of the plane is 2.4 km, a flare is released, which hits the target on the ground. **(a) What is the angle θ?** The diagram shows the following details: - A right triangle is formed with the horizontal, the initial line of motion, and a line to the target. - The horizontal distance to the target is indicated as 2.4 km. - The initial velocity of the plane is 240 m/s at an angle of 30.0°. - Calculations are visible where the angle θ is determined using trigonometric functions. - The result shows θ = 60°. **(b) What is the final speed of the flare right before it hits the ground and what angle does this make below the horizontal? Note: This is not the same angle as in part (a).** Additional analysis is made for this section: - Another diagram shows the path of the flare with vectors representing velocity components. - The final calculations indicate a final speed. - There is a note indicating the angle found differs from part (a). - The calculated angle is approximately +28.27°. **Graphs/Diagrams:** - The diagram shows a trajectory of the flare released at 30.0° from the horizontal, marking its path through a parabolic motion until it hits the target. - Annotation on the diagram includes trigonometric identities and resolved vectors. - Red and black inks are used to highlight steps and comments in solution calculations. This problem requires knowledge of kinematic equations, vector resolution, and trigonometry for complete analysis.
Transcribed Image Text:**Problem 14: Projectile Motion/Kinematics 2D** **Scenario:** An airplane is flying with a velocity of 240 m/s at an angle of 30.0° with the horizontal. When the altitude of the plane is 2.4 km, a flare is released, which hits the target on the ground. **(a) What is the angle θ?** The diagram shows the following details: - A right triangle is formed with the horizontal, the initial line of motion, and a line to the target. - The horizontal distance to the target is indicated as 2.4 km. - The initial velocity of the plane is 240 m/s at an angle of 30.0°. - Calculations are visible where the angle θ is determined using trigonometric functions. - The result shows θ = 60°. **(b) What is the final speed of the flare right before it hits the ground and what angle does this make below the horizontal? Note: This is not the same angle as in part (a).** Additional analysis is made for this section: - Another diagram shows the path of the flare with vectors representing velocity components. - The final calculations indicate a final speed. - There is a note indicating the angle found differs from part (a). - The calculated angle is approximately +28.27°. **Graphs/Diagrams:** - The diagram shows a trajectory of the flare released at 30.0° from the horizontal, marking its path through a parabolic motion until it hits the target. - Annotation on the diagram includes trigonometric identities and resolved vectors. - Red and black inks are used to highlight steps and comments in solution calculations. This problem requires knowledge of kinematic equations, vector resolution, and trigonometry for complete analysis.
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