Problem 13.3.5: Suppose heat is lost from the lateral surface of a thin rod of length L into a surrounding medium at temperature zero. If the linear law of heat transfer applies, then the heat equation takes on the form a?u k əx? ди · hu = 0 < x < L, t> 0 where h is a constant. Find the temperature u(x,t) if the initial temperature is f (x) throughout and the ends x = 0 and x = L are insulated. See figure below.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Problem 13.3.5: Suppose heat is lost from the lateral surface of a thin rod of
length L into a surrounding medium at temperature zero. If the linear law of heat
transfer applies, then the heat equation takes on the form
a²u
k
əx²
ди
һи —
at'
0 < x < L,
t > 0
where h is a constant. Find the temperature u(x,t) if the initial temperature is
f (x) throughout and the ends x = 0 and x = L are insulated. See figure below.
insulated
0°
insulated
L
0°
heat transfer from
lateral surface of
the rod
Transcribed Image Text:Problem 13.3.5: Suppose heat is lost from the lateral surface of a thin rod of length L into a surrounding medium at temperature zero. If the linear law of heat transfer applies, then the heat equation takes on the form a²u k əx² ди һи — at' 0 < x < L, t > 0 where h is a constant. Find the temperature u(x,t) if the initial temperature is f (x) throughout and the ends x = 0 and x = L are insulated. See figure below. insulated 0° insulated L 0° heat transfer from lateral surface of the rod
We can expand f (x) into its Fourier series (sine only)
E Bu sin ( ) - bn sin (x)
Ex) = f(x) - I
B, Sin
%3D
n=1
with
2
(-)
bn
f (x) sin
x ) dx
Compare coefficients and find B, = bn and find the same answer as before:
Σ
-n?n?
at
L2
2
y(x, t) :
L
(x)e
f(x) sin
-x) dx ) sin
L
n=1
Transcribed Image Text:We can expand f (x) into its Fourier series (sine only) E Bu sin ( ) - bn sin (x) Ex) = f(x) - I B, Sin %3D n=1 with 2 (-) bn f (x) sin x ) dx Compare coefficients and find B, = bn and find the same answer as before: Σ -n?n? at L2 2 y(x, t) : L (x)e f(x) sin -x) dx ) sin L n=1
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