Problem 118 IR Spectrum (liquid film) 1698 4000 3000 2000 1600 1200 800 v (cm") 100 Mass Spectrum UV Spectrum 80 M*. 136 A max 277 nm (log10€ 4.2) solvent : methanol 92 107 22 20 C3HBO2 160 m/e 40 80 120 200 240 280 13C NMR Spectrum (100.0 MHz, CDCI, solution) DEPT CH сH снt solvent proton decoupled 200 160 120 80 40 O 8 (ppm) expansion 'H NMR Spectrum (400 MHz, CDCI, solution) 7.65 7.45 6.85 6.65 ppm TMS 10 8 7 6 4 3 2 8 (ppm) % of base peak

Problem 7 2249 IR Spectrum (KBr disc) 4000 3000 2000 1600 1200 800 v (cm') 100 Mass Spectrum 80 53 60 No significant UV 40 M+' = 80 absorption above 220 nm 40 20 C4HẠN2 160 m/e 40 80 120 200 240 280 T 13C NMR Spectrum (100.0 MHz, CDCI, solution) DEPT CHat CH, сн+ proton decoupled solvent 200 160 120 80 40 8 (ppm) H NMR Spectrum (400 MHz, CDCI, solution) TMS 10 1 8 (ppm) 9 7 6. 4 % of base peak 5

Consider a molecule with the molecular formula C7H8O2   Draw a structure based on the data given.

Macmillan Learning λ (nm) EA (M-1cm-1) EB (M-1cm-1) EC (M1cm-1) 450 3200 10900 19300 5900 9400 10100 27500 12200 3500 480 Spectroscopic data for three organic dyes, A, B, and C, are shown in the table. A solution containing a mixture of the three dyes in a 1.000 cm cuvet had absorbances of 0.5906 at 450 nm, 0.4340 at 480 nm, and 0.6873 at 520 nm. Find the concentrations of the three dyes in the solutions. For each solution, the zero is set with a blank. 520 [A] = [B] = [C] = M M M

Please elaborate the steps to finding the answer for this unknown spectroscopy?

121 Problem 15 IR Spectrum (lquid fam) 4000 3000 2000 1600 1200 800 v (cm') 100- 43 Mass Spectrum 80 60 40 No significant UV M* 122/124 absorption above 220 nm 20 C3H,Br trum wou 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50 0 MHz. CDCI, solution) pled scouple DEPT CH CHt CHt 20 solvent proton decoupled Spect 200 160 120 80 40 8 (ppm) H NMR Spectrum (200 MHz, CDCI, solution) expansions 4.6 40 ppm 20 14 ppm TMS 业 10 9 8 7 6 5 4 3 2 8 (ppm) 104 Sof base peak

Question 19 of 27 > Graphs are a common data analysis tool used in all branches of science. The given graph represents how light absorbance at 423 nm varies with concentration of an organic dye. Identify the parts of the graph. Answer Bank y = 0.210x – 0.032 line equation Title Abs423 Dye Conc. (nM) best-fit line 0 i 2 3 4 5 6 7 8 9 10

4

Identify the peaks and the structure.

.    Analysis    of    13C-NMR    spectrum:Observations _________     Inferences________