PROBLEM 11.46 Car A is parked along the northbound lane of a highway, and car B is traveling in the southbound lane at a constant speed of 60 mi/h. At 1=0, A starts and accelerates at a constant rate a,, while at t=5 s, B begins to slow down with a constant deceleration of magnitude a 16. Knowing that when the cars pass each other x= 294 ft and v =vg, determine (a) the acceleration a, (b) when the vehicles pass each other, (c) the distance d between the vehicles at 1=0. (60 mi/h

Elements Of Electromagnetics
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PROBLEM 11.46
Car A is parked along the northbound lane of a highway, and car B is traveling in the southbound lane at a
constant speed of 60 mi/h. Att=0, A starts and accelerates at a constant rate a, while at t=5s, B begins to
slow down with a constant deceleration of magnitude a 16. Knowing that when the cars pass each other
x = 294 ft and v =VR, determine (a) the acceleration a, (b) when the vehicles pass each other, (c) the
distance d between the vehicles at t=0.
(-60 mi/h
(l 0
Name - Mortada Ali
SOLUTION
Qassem
VA =0+a,t
Xg =0+(vg)ot (và)o =60 mi/h = 88 ft/s
Xg = (88 ft/s)(5 s) = 440 ft
1
Va = ("g), + a»(t – 5) ag =--a,
Assume t> 5 s when the cars pass each other.
At that time (t AB ),
VA = VB:
astAB = (88 ft/s) –
-(1 AB
-5)
294 ft =ai.
= 294 ft:
a,(공AB-8)- 88
Then
%3D
294
441B - 343t AB + 245 = 0
or
Hey I want a nice
handwriting please
with my name the
same solution
Transcribed Image Text:PROBLEM 11.46 Car A is parked along the northbound lane of a highway, and car B is traveling in the southbound lane at a constant speed of 60 mi/h. Att=0, A starts and accelerates at a constant rate a, while at t=5s, B begins to slow down with a constant deceleration of magnitude a 16. Knowing that when the cars pass each other x = 294 ft and v =VR, determine (a) the acceleration a, (b) when the vehicles pass each other, (c) the distance d between the vehicles at t=0. (-60 mi/h (l 0 Name - Mortada Ali SOLUTION Qassem VA =0+a,t Xg =0+(vg)ot (và)o =60 mi/h = 88 ft/s Xg = (88 ft/s)(5 s) = 440 ft 1 Va = ("g), + a»(t – 5) ag =--a, Assume t> 5 s when the cars pass each other. At that time (t AB ), VA = VB: astAB = (88 ft/s) – -(1 AB -5) 294 ft =ai. = 294 ft: a,(공AB-8)- 88 Then %3D 294 441B - 343t AB + 245 = 0 or Hey I want a nice handwriting please with my name the same solution
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