Problem 11.2.19. Since the convergence of Cauchy sequences can be taken as the completeness axiom for the real number system, it does not hold for the rational number system. Give an example of a Cauchy sequence of rational numbers which does not converge to a rational number.

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Real math analysis, I need help with problem 11.2.19.

thank you so much.

Problem 11.2.19. Since the convergence of Cauchy sequences can be taken
as the completeness axiom for the real number system, it does not hold for the
rational number system. Give an example of a Cauchy sequence of rational
numbers which does not converge to a rational number.
Transcribed Image Text:Problem 11.2.19. Since the convergence of Cauchy sequences can be taken as the completeness axiom for the real number system, it does not hold for the rational number system. Give an example of a Cauchy sequence of rational numbers which does not converge to a rational number.
Theorem 11.2.15. Cauchy sequences converge
Suppose (sn) is a Cauchy sequence of real numbers. There exists a real number s
such that limn→∞ Sn = s.
Sketch of Proof. We know that (sn) is bounded, so by the Bolzano-Weierstrass
Theorem, it has a convergent subsequence (Snk) converging to some real
number s. We have sn – s = |Sn – Snp + Snk
s| < |Sn – Sni|+|Snk
8|. If we
choose n and ng large enough, we should be able to make each term arbitrarily
small.
Transcribed Image Text:Theorem 11.2.15. Cauchy sequences converge Suppose (sn) is a Cauchy sequence of real numbers. There exists a real number s such that limn→∞ Sn = s. Sketch of Proof. We know that (sn) is bounded, so by the Bolzano-Weierstrass Theorem, it has a convergent subsequence (Snk) converging to some real number s. We have sn – s = |Sn – Snp + Snk s| < |Sn – Sni|+|Snk 8|. If we choose n and ng large enough, we should be able to make each term arbitrarily small.
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