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Problem 11.13 Prepare plots f vs P and phi vs P for isopropanol at 200 °C for the pressure range from 0 to 50 bar. For the vapor phase, values of Z ar given by Z 19.86* 10-³P - 11.41 * 10-5p² where P is in bars. The vapor pressure of isopropanol at 200 °C is 31.92 bar, and the liquid phase isothermal compressibility k at 200 °C is 0.3*10-3 bar¹, independent of P. Rackett Equation Vsat = VcZ(1-1)0.2857

Problem 11.13 Prepare plots f vs P and phi vs P for isopropanol at 200 °C for the pressure range from 0 to 50 bar. For the vapor phase, values of Z ar given by Z 19.86* 10-³P - 11.41 * 10-5p² where P is in bars. The vapor pressure of isopropanol at 200 °C is 31.92 bar, and the liquid phase isothermal compressibility k at 200 °C is 0.3*10-3 bar¹, independent of P. Rackett Equation Vsat = VcZ(1-1)0.2857

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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Problem 11.13 Prepare plots f vs P and phi vs P for isopropanol at 200 °C for the pressure range from 0 to 50 bar. For the vapor phase, values of Z ar given by Z 19.86* 10-³P - 11.41 * 10-5p² where P is in bars. The vapor pressure of isopropanol at 200 °C is 31.92 bar, and the liquid phase isothermal compressibility k at 200 °C is 0.3*10-3 bar¹, independent of P. Rackett Equation Vsat = VcZ(1-1)0.2857
Transcribed Image Text:Problem 11.13 Prepare plots f vs P and phi vs P for isopropanol at 200 °C for the pressure range from 0 to 50 bar. For the vapor phase, values of Z ar given by Z 19.86* 10-³P - 11.41 * 10-5p² where P is in bars. The vapor pressure of isopropanol at 200 °C is 31.92 bar, and the liquid phase isothermal compressibility k at 200 °C is 0.3*10-3 bar¹, independent of P. Rackett Equation Vsat = VcZ(1-1)0.2857
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