Problem 1.6.10. Imagine a life guard situated a distance dı from the water. Hesees a swimmer in distress a distance L to his left and distance d2 from the shore.v1 > 02.what trajectory will get him to the swimmer in the least time? Does he rush towardsthe victim in a straight line joining them, does he first run on land until he is infront of the victim and then swim, does he head for the water first and then swimGiven that his speed on land and water are vị and v2 respectively, withline segments in each medium (why) and show that for the least time sin 6where the angles O; are the angles of the segments with respect to the normalover, or does he do something else? Pick some trajectory composed of two stretsin 02%3DU2the shoreline.This problem has an analog in optics. If light is emitted at a point in a mediumwhere its velocity is vi and arrives at a point in an adjacent medium where invelocity is v2, the route it takes is arrived at in the same fashion since light takesthe path of least time. The above equation is called Snell's Law.

The velocity of the guard on the shore is greater than the velocity in the water. So, the guard need…

Answered: Problem 1.6.10. Imagine a life guard…

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