Problem 1.3. The building in Fig. P1.1 is used for general office space. The slab is 8 in. thick. The beams are 12 in. wide and have a total depth of 18 in., the bay dimensions are 18.5 ft in the X direction and 21 ft in the Y direction, and the superimposed service dead load is 25 psf. Calculate the slab factored load in psf and the beam factored load in klf. Comment on your solution in comparison with Problem 1.

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Problem 1.3. The building in Fig. P1.1 is used for general office space. The slab is 8 in. thick.
The beams are 12 in. wide and have a total depth of 18 in., the bay dimensions are 18.5 ft in the
X direction and 21 ft in the Y direction, and the superimposed service dead load is 25 psf.
Calculate the slab factored load in psf and the beam factored load in klf. Comment on your
solution in comparison with Problem 1.1.
Transcribed Image Text:Problem 1.3. The building in Fig. P1.1 is used for general office space. The slab is 8 in. thick. The beams are 12 in. wide and have a total depth of 18 in., the bay dimensions are 18.5 ft in the X direction and 21 ft in the Y direction, and the superimposed service dead load is 25 psf. Calculate the slab factored load in psf and the beam factored load in klf. Comment on your solution in comparison with Problem 1.1.
8)
-7 bays @y-yy":
A
Plan
-5-
-4-
-3-
-2-
Elevation
Fig. P1.1
-5 @ 12'-0"
4 bays@x'-xx
Transcribed Image Text:8) -7 bays @y-yy": A Plan -5- -4- -3- -2- Elevation Fig. P1.1 -5 @ 12'-0" 4 bays@x'-xx
Expert Solution
Step 1

volume of slab 8×12×18=1728=0.028m3

density of Rcc= 2500kg/m3

dead load 0.028×2500=70 

total load=70+25=95 

total slab factored load=factored dead load+factored live load

                                     =1.4×70+1.7×25

total slab factored load=140.5psf

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