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Problem 1.3 Mazzoldi Four point charges of equal value q = 10°C are placed at the vertices of a square with side a = 10 cm. Calculate the electrostatic potential energy of the system and the work necessary to move one of the charges from the initial position P to the point Pz indicated in the figure and located in the center of the side. P 15/30

Problem 1.3 Mazzoldi Four point charges of equal value q = 10°C are placed at the vertices of a square with side a = 10 cm. Calculate the electrostatic potential energy of the system and the work necessary to move one of the charges from the initial position P to the point Pz indicated in the figure and located in the center of the side. P 15/30

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?I sent the solution along with the question, but how are there 6 pair of charges? And what were the formulas used? In general can you give an explanation of what he did to solve it in simpler terms?
Problem 1.3 Mazzoldi Four point charges of equal value q = 10°C are placed at the vertices of a square with side a = 10 cm. Calculate the electrostatic potential energy of the system and the work necessary to move one of the charges from the initial position P to the point P2 indicated in the figure and located in the center of the side. 15/30
Transcribed Image Text:Problem 1.3 Mazzoldi Four point charges of equal value q = 10°C are placed at the vertices of a square with side a = 10 cm. Calculate the electrostatic potential energy of the system and the work necessary to move one of the charges from the initial position P to the point P2 indicated in the figure and located in the center of the side. 15/30
Solution 1.3 Mazzoldi 6 pairs of charges. The expression for the electrostatic potential energy of the system becomes: There are 1 qiqj qiqj 2q? Ue[1] =; = 4.87-10-5J 2+ – 4TEorij itj 4teorij i<j V2 It is necessary to calculate the electrostatic energy of the new configuration (indicated with [2]). 2q 4TE02/2 q? q? U[2] = 1 2+ 2, 6.84-10 5J 4TCoa 4TEQV5/2a W = Ue[2] – 4)=1.97- 10-5J 16/30
Transcribed Image Text:Solution 1.3 Mazzoldi 6 pairs of charges. The expression for the electrostatic potential energy of the system becomes: There are 1 qiqj qiqj 2q? Ue[1] =; = 4.87-10-5J 2+ – 4TEorij itj 4teorij i<j V2 It is necessary to calculate the electrostatic energy of the new configuration (indicated with [2]). 2q 4TE02/2 q? q? U[2] = 1 2+ 2, 6.84-10 5J 4TCoa 4TEQV5/2a W = Ue[2] – 4)=1.97- 10-5J 16/30
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