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Problem 1.2: The equation below gives the boiling temperature of isopropanol as a function of pressure: B A-log10 P where Tis in kelvin, P is in bar, and the parameters A, B, and Care A = 4.57795, B = 1221.423, C=-87.474. T= C,

Problem 1.2: The equation below gives the boiling temperature of isopropanol as a function of pressure: B A-log10 P where Tis in kelvin, P is in bar, and the parameters A, B, and Care A = 4.57795, B = 1221.423, C=-87.474. T= C,

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Problem 1.2: The equation below gives the boiling temperature of isopropanol as a function of pressure: B A - log10 P where T is in kelvin, P is in bar, and the parameters A, B, and Care A = 4.57795, B = 1221.423, C=-87.474. 1.6 Problems T = C₁ Obtain an equation that gives the boiling temperature in °F, as a function of In P, with P in psi. Hint: The equation is of the form B' A' - In P but the constants A', B', and C' have different values from those given above. T= 27
Transcribed Image Text:Problem 1.2: The equation below gives the boiling temperature of isopropanol as a function of pressure: B A - log10 P where T is in kelvin, P is in bar, and the parameters A, B, and Care A = 4.57795, B = 1221.423, C=-87.474. 1.6 Problems T = C₁ Obtain an equation that gives the boiling temperature in °F, as a function of In P, with P in psi. Hint: The equation is of the form B' A' - In P but the constants A', B', and C' have different values from those given above. T= 27
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