Problem 1. Two undisturbed soil samples, each having a volume of 0.1 ft³, are collected from different depths of the same soil layer. For sample A, located above the groundwater table, W= 11 lb and w= 9%. Sample B is located below the groundwater table. If G3= 2.68, determine: a. Void ratio of A b. Degree of saturation of A c. Water content of B d. Total weight of B
Problem 1. Two undisturbed soil samples, each having a volume of 0.1 ft³, are collected from different depths of the same soil layer. For sample A, located above the groundwater table, W= 11 lb and w= 9%. Sample B is located below the groundwater table. If G3= 2.68, determine: a. Void ratio of A b. Degree of saturation of A c. Water content of B d. Total weight of B
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
100%
Unit weight of water is 62.4 pcf.
How would you find the volumes of water vs soil/solid and how much air their is for soil A when not fully saturated?
See images for problem information and equations known.

Transcribed Image Text:30%, and 60% finer on grain-size curve
Vv
Vv
e= void ratio
Vs
V-Vv
V volume of void
V volume of solid
V= total volume
Vv
n= porosity=
%3D
V
Vw
S= Degree of Saturation=.
x 100%
Vv
Vw=volume of water
Ww
w=water content=
Ws
Ww weight of water
Ws = weight of solids
W
y= unit weight=-
V
Ws
Ya = dry unit weight=
V
Ws
Unit weight of solids: Ys
Vs
Ws
Ys
Gs= specific gravity=;
Yw
VsYw
Yw= 62.4 pcf= 9.81 kN/m³= 1 ton/m3
%3D
Ys
Yd=
1+w
1+e
wGs = Se
GSYW
%3D
Ys
%D
ton
Unit weight of water: Yw = 9.81 kN/.
= 1
m3
m3
62.4 pcf

Transcribed Image Text:Problem 1. Two undisturbed soil samples, each
having a volume of 0.1 ft3, are collected from
different depths of the same soil layer. For sample
A, located above the groundwater table, W= 11 lb
and w= 9%. Sample B is located below the
groundwater table. If G3= 2.68, determine:
a. Void ratio of A
b. Degree of saturation of A
c. Water content of B
d. Total weight of B
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