Problem #1. The pressure on a closed tank reads 58.86 kPa. a. What is the equivalent height in water? b. What is the equivalent height in terms of oil having a specific gravity of 0.85? c. What is the equivalent height in terms of mercury having a specific gravity of 13.6?
Problem #1. The pressure on a closed tank reads 58.86 kPa. a. What is the equivalent height in water? b. What is the equivalent height in terms of oil having a specific gravity of 0.85? c. What is the equivalent height in terms of mercury having a specific gravity of 13.6?
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Problem #1. The pressure on a closed tank reads 58.86 kPa.
a. What is the equivalent height in water?
b. What is the equivalent height in terms of oil having a specific gravity of
0.85?
c. What is the equivalent height in terms of mercury having a specific gravity
of 13.6?
Problem #2. A vertical triangular plate whose height is 3.6 meters has its base horizontal
and vertex upper most in the water surface.
a. Find the depth to which it must be lowered from its vertex so that the
difference in level between the center of gravity and the center of
pressure shall be 20cm.
b. How far is the center of pressure below the water surface?
c. What is the base width of the plate if the total hydrostatic force acting on
the plate is 76.28 kN?
Problem #3. The 6 ft. diameter cylinder weighs 5000 lb. and 5 ft. long.
a. Determine the upward force due to the effect of oil in the left side.
b. Compute the horizontal reaction at A.
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