Problem #1. The pressure on a closed tank reads 58.86 kPa.a. What is the equivalent height in water?b. What is the equivalent height in terms of oil having a specific gravity of0.85?c. What is the equivalent height in terms of mercury having a specific gravityof 13.6?Problem #2. A vertical triangular plate whose height is 3.6 meters has its base horizontaland vertex upper most in the water surface.a. Find the depth to which it must be lowered from its vertex so that thedifference in level between the center of gravity and the center ofpressure shall be 20cm.b. How far is the center of pressure below the water surface?c. What is the base width of the plate if the total hydrostatic force acting onthe plate is 76.28 kN?Problem #3. The 6 ft. diameter cylinder weighs 5000 lb. and 5 ft. long.a. Determine the upward force due to the effect of oil in the left side.b. Compute the horizontal reaction at A.

Answered: Image /qna-images/answer/59536a4a-5210-4dc4-aa1a-ff0c0d3258b4.jpg

Problem #1. The pressure on a closed tank reads 58.86 kPa. a. What is the equivalent height in water? b. What is the equivalent height in terms of oil having a specific gravity of 0.85? c. What is the equivalent height in terms of mercury having a specific gravity of 13.6?

Problem #1. The pressure on a closed tank reads 58.86 kPa. a. What is the equivalent height in water? b. What is the equivalent height in terms of oil having a specific gravity of 0.85? c. What is the equivalent height in terms of mercury having a specific gravity of 13.6?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Refer to the picture below to solve the following problems
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