Problem 1. The gauge pressure of the air in the tank shown in the figure below is meası.red to be 65 kPa (fluids’ densities as follows: Pµ20 = 1000 Kg m3, Poil = 742 Kg/m², pHg = 13650 Kg/m³). Determine the differential height a) h of the mercury column Oil 65 kPa Determine the resultant force per b) unit depth acting on the quarter of circumference (radius R=15 cm) at the 75 cm Air Water left bottom corner of the tank. 30 cm Mercury

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Properties of Fluids

The term fluid represents a type of substance that can easily change its shape under any external pressure/force and can flow. Fluids can acquire any shape in which it is stored and can resist normal stresses but cannot resist shear stress in rest condition. Whenever external shear stress is applied to fluids, it starts to flow. The fluids may be liquid or gas. Example- water, air, etc.