Problem 1. A particular optometry patient is nearsighted. The most distant object that she can focus on is 40 cm in front of her eye. The closest object that she can focus on is 20 cm in front of her eye. (In technical terms, her 'far point' is 40 cm and her 'near point' is 20 cm. The fact that these are different is because her eye's lens has a variable focal length.) (a) The 'refractive power' of a lens is equal to 1/f, and a diopter D is equal to an inverse meter. Find the refractive power in diopters of the lens, including its sign and type (converging or diverging) that will correct this patient's vision. (b) Given the lens found in part (a), what is the new effective near point for the person while wearing her glasses? (In other words, what is the closest object that she can focus on?) (c) What is the apparent (angular) magnification of her eye, as viewed by someone relatively far from her face? Assume that the corrective lens is 2 cm from her eye. (d) If her lens has a 'progressive' correction (or a separate bifocal) of +1.0 D, that means that the lower portion of the lens has a refractive power equal to the original power plus one. How much does this correction improve her near point, if she is looking through the bottom of the lens (e.g. while reading)?

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Problem 1. A particular optometry patient is nearsighted. The most distant object that she can
focus on is 40 cm in front of her eye. The closest object that she can focus on is 20 cm in front of
her eye. (In technical terms, her 'far point' is 40 cm and her 'near point' is 20 cm. The fact that
these are different is because her eye's lens has a variable focal length.)
(a) The 'refractive power' of a lens is equal to 1/f, and a diopter D is equal to an inverse meter.
Find the refractive power in diopters of the lens, including its sign and type (converging or
diverging) that will correct this patient's vision.
(b) Given the lens found in part (a), what is the new effective near point for the person while
wearing her glasses? (In other words, what is the closest object that she can focus on?)
(c) What is the apparent (angular) magnification of her eye, as viewed by someone relatively far
from her face? Assume that the corrective lens is 2 cm from her eye.
(d) If her lens has a 'progressive' correction (or a separate bifocal) of +1.0 D, that means that
the lower portion of the lens has a refractive power equal to the original power plus one. How
much does this correction improve her near point, if she is looking through the bottom of the
lens (e.g. while reading)?
Transcribed Image Text:Problem 1. A particular optometry patient is nearsighted. The most distant object that she can focus on is 40 cm in front of her eye. The closest object that she can focus on is 20 cm in front of her eye. (In technical terms, her 'far point' is 40 cm and her 'near point' is 20 cm. The fact that these are different is because her eye's lens has a variable focal length.) (a) The 'refractive power' of a lens is equal to 1/f, and a diopter D is equal to an inverse meter. Find the refractive power in diopters of the lens, including its sign and type (converging or diverging) that will correct this patient's vision. (b) Given the lens found in part (a), what is the new effective near point for the person while wearing her glasses? (In other words, what is the closest object that she can focus on?) (c) What is the apparent (angular) magnification of her eye, as viewed by someone relatively far from her face? Assume that the corrective lens is 2 cm from her eye. (d) If her lens has a 'progressive' correction (or a separate bifocal) of +1.0 D, that means that the lower portion of the lens has a refractive power equal to the original power plus one. How much does this correction improve her near point, if she is looking through the bottom of the lens (e.g. while reading)?
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