Problem 1. A particular optometry patient is nearsighted. The most distant object that she can focus on is 40 cm in front of her eye. The closest object that she can focus on is 20 cm in front of her eye. (In technical terms, her 'far point' is 40 cm and her 'near point' is 20 cm. The fact that these are different is because her eye's lens has a variable focal length.) (a) The 'refractive power' of a lens is equal to 1/f, and a diopter D is equal to an inverse meter. Find the refractive power in diopters of the lens, including its sign and type (converging or diverging) that will correct this patient's vision. (b) Given the lens found in part (a), what is the new effective near point for the person while wearing her glasses? (In other words, what is the closest object that she can focus on?) (c) What is the apparent (angular) magnification of her eye, as viewed by someone relatively far from her face? Assume that the corrective lens is 2 cm from her eye. (d) If her lens has a 'progressive' correction (or a separate bifocal) of +1.0 D, that means that the lower portion of the lens has a refractive power equal to the original power plus one. How much does this correction improve her near point, if she is looking through the bottom of the lens (e.g. while reading)?

Q: How far from a converging lens with a focal length of 41  cm  should an object be placed to produce…

A:

Q: I-16) Which is the most likely image corresponding to the FFT to the right? A B C D

A:

Q: Why do you need greater intensity for a low-level image than a high-level one

A: Introduction:- Intensity is the amount of light or energy that is present in an image. It is usually…

Q: Use this table and determine the image characteristics ( is the image larger than the object or…

A: The magnification of a lens is given as m = v/u where v is the length of the image and u is the…

Q: 2: Magnetic Force on a Rectangular Coil as a Function of the Length (L): Current (A) 4.0 Length of…

A:

Q: The focal length of a diverging lens is negative.  If f=-13cm for a particular diverging lens, where…

A:

Q: Write a problem with this image

A: We are given the potential difference of any body say a battery here. We are given the graph of this…

Q: A candle with Sem height is placed in front of a diverging lens. The object is 15 cm in front of the…

A:

Q: You place an object a distance of 55 cm in front of a diverging lens with a focal length of…

A: Given data The distance of the object from the lens is u=55 cm The focal length of the lens is f=20…

Q: An object is 40 cm in front of a concave mirror with focal length of 20 cm. what is the postition of…

A: Required:Position of image using ray tracing.

Q: Tmages Form The Front Вack A and Image the 1 Object F Optical axis do- engths 2.

A: It is a convex mirror

Q: An apple, 6.2 cm tall, is situated 1.2 m from a lens.  If the image formed is located on the same…

A:

Q: .

A: It is given that the radius of the lens is 100 mm and the refractive index of its material is 1.60.…

Q: A diverging lens has a focal length of 12 cm.  A 5 cm object is placed 46 cm from the lens.…

A: Given data: Focal length of lens is, f=12 cm. Height of object is, ho=5 cm. Object distance is, u=46…

Q: As you sit in your parked car, you glance in the convex side mirror (radius of curvature 125 cm) and…

A:

Q: A 5.3 cm high object is placed 21 cm away from a lens with focal length -6.4 cm. Calculate the…

A:

Q: By what factor is the image magnified when an object is placed 1.50 focal lengths from a converging…

A:

Q: Does the apparent depth of a tank of water change if viewed obliquely? If so, does the apparent…

A: Yes, the apparent depth of a tank of water changes if viewed obliquely.

Q: (8) A thin lens is made from material having an index of refraction of 1.65. The front surface of…

A: The focal length of the lens is calculated with lens makers formula .By substituting the radii of…

Q: Calculate the height of the image formed when a 2.5 cm tall object is placed 10 cm away trom a lence…

A:

Q: A 2 cm high object is viewed through a diverging lens with a -12 cm focal point. If the object is 8…

A: Height of the object is Hi = 2 cm  Focal length of the diverging lens is f = - 12 cm  Object…

Q: A 4.99 mm high diamond is placed on the axis of, and 12.7 cm from, a lens with a focal length of…

A:

Q: An object 2.00 cm high is placed 39.6 cm to the left of a converging lens having a focal length of…

A:

Refraction of Light

Refraction is a change in the direction of light rays when they travel from one medium to another. It is the bending of light when it goes through different media.

Angle of Refraction

Light is considered by many scientists to have dual nature, both particle nature and wave nature. First, Particle nature is one in which we consider a stream of packets of energy called photons. Second, Wave nature is considering light as electromagnetic radiation whereas part of it is perceived by humans. Visible spectrum defined by humans lies in a range of 400 to 700 nm wavelengths.

Index of Refraction of Diamond

Diamond, the world’s hardest naturally occurring material and mineral known, is a solid form of the element carbon. The atoms are arranged in a crystal structure called diamond cubic. They exist in a huge variety of colours. Also, they are one of the best conductors of heat and have a very high melting point.