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Problem 1 What is the value of 4(ӕ — 2) (х — 3) + 7(а — 2) (ӕ — 5) — 6(г — 3) (ӕ — 5) - - when x = = 5? Problem 2 Which polynomial function has zeros when x = -2, 3, 5? 4? А: f(2) — (z — 2)(3а + 4) (х + 5) || B: f(x) = (x – 2)(4æ + 3)(x + 5) | C: f(x) = (x + 2)(3x – 4)(x + 5) D: f(«) %3D (ӕ + 2)(4л — 3) (ӕ — 5) -

Problem 1 What is the value of 4(ӕ — 2) (х — 3) + 7(а — 2) (ӕ — 5) — 6(г — 3) (ӕ — 5) - - when x = = 5? Problem 2 Which polynomial function has zeros when x = -2, 3, 5? 4? А: f(2) — (z — 2)(3а + 4) (х + 5) || B: f(x) = (x – 2)(4æ + 3)(x + 5) | C: f(x) = (x + 2)(3x – 4)(x + 5) D: f(«) %3D (ӕ + 2)(4л — 3) (ӕ — 5) -

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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please help, i need problems 1-4 answered
Problem 1 What is the value of 4(а — 2) (г — 3) + 7(а — 2)(ӕ — 5) — 6(г — 3) (ӕ — 5) - - when x = 5? Problem 2 Which polynomial function has zeros when 3 x = -2, , 5? А: f(æ) = (x – 2)(3x + 4)(x + 5) - B: f(æ) — (х — 2)(4 + 3)(ӕ + 5) - C: f(x) = (x+ 2)(3æ – 4)(x + 5) - D: f(«) — (х + 2)(4л — 3) (х — 5) - -
Transcribed Image Text:Problem 1 What is the value of 4(а — 2) (г — 3) + 7(а — 2)(ӕ — 5) — 6(г — 3) (ӕ — 5) - - when x = 5? Problem 2 Which polynomial function has zeros when 3 x = -2, , 5? А: f(æ) = (x – 2)(3x + 4)(x + 5) - B: f(æ) — (х — 2)(4 + 3)(ӕ + 5) - C: f(x) = (x+ 2)(3æ – 4)(x + 5) - D: f(«) — (х + 2)(4л — 3) (х — 5) - -
Problem 3 The graph of a polynomial f(x) = (2x – 3)(x – 4)(x +3) has x-intercepts at 3 x values. What are they? Problem 4 Match each sequence with one of the recursive definitions. Note that only the part of the definition showing the relationship between the current term and the previous term is given so as not to give away the solutions. One of the sequences matches two recursive definitions. А: a(n) = a(n – 1) – 4 b(п) — 6(п — 1) +о C: c(n) = - · c(n – 1) D: d(n) = 1. d(n – 1) 1: 7, 3, -1, -5 2: 1,-3,1,- 3: 8, 8, 8, 8 B:
Transcribed Image Text:Problem 3 The graph of a polynomial f(x) = (2x – 3)(x – 4)(x +3) has x-intercepts at 3 x values. What are they? Problem 4 Match each sequence with one of the recursive definitions. Note that only the part of the definition showing the relationship between the current term and the previous term is given so as not to give away the solutions. One of the sequences matches two recursive definitions. А: a(n) = a(n – 1) – 4 b(п) — 6(п — 1) +о C: c(n) = - · c(n – 1) D: d(n) = 1. d(n – 1) 1: 7, 3, -1, -5 2: 1,-3,1,- 3: 8, 8, 8, 8 B:
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