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Problem 1) Use superposition to determine what value of the voltage source Vx will result in a voltage Vo = 0 V. 06 mA cont →→ Vx=0 (short) Circult) tribution make Vx a → Vx=1 VE need to multiply Vx by something V₂0₂2 to make V. exactly cancel out w/ bmA ² Y₂ = 8 6 ΚΩ 6 mA 4 ΚΩ 4 ΚΩ Vx + o=\x 3 8 ΚΩ Vo

Problem 1) Use superposition to determine what value of the voltage source Vx will result in a voltage Vo = 0 V. 06 mA cont →→ Vx=0 (short) Circult) tribution make Vx a → Vx=1 VE need to multiply Vx by something V₂0₂2 to make V. exactly cancel out w/ bmA ² Y₂ = 8 6 ΚΩ 6 mA 4 ΚΩ 4 ΚΩ Vx + o=\x 3 8 ΚΩ Vo

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Problem 1) Use superposition to determine what value of the voltage source Vx will result in a Vo = 0 V. voltage 06 mA cont →→ Vx=0 (short) circuit) tribution make Vx a → Vx=1 V need to multiply Vx by something if Vo=0.2 to make V. exactly cancel out w/ bmA to make Vo = 0 6 ΚΩ 6 mA 4 ΚΩ 4 ΚΩ 0=√x + Vx 8 ΚΩ + Vo 0
Transcribed Image Text:Problem 1) Use superposition to determine what value of the voltage source Vx will result in a Vo = 0 V. voltage 06 mA cont →→ Vx=0 (short) circuit) tribution make Vx a → Vx=1 V need to multiply Vx by something if Vo=0.2 to make V. exactly cancel out w/ bmA to make Vo = 0 6 ΚΩ 6 mA 4 ΚΩ 4 ΚΩ 0=√x + Vx 8 ΚΩ + Vo 0
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