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PROBLEM 1 or the truss shown in SD-001, The strength of the truss is assumed to be governed by the strength of member CD. Use Fy = 248 MPa and E = 200 GPa. The member CD is composed of two sections placed back-to-back separated by s = 6 mm as shown. Properties of one channel A = 1774 mm2 Ix = 1.60 x 10^6 mm^4 ly = 0.13 x 10^6 mm^4 x 11.60 mm Jsing NSCP 2015 and ASD, calculate the safe value of P.

PROBLEM 1 or the truss shown in SD-001, The strength of the truss is assumed to be governed by the strength of member CD. Use Fy = 248 MPa and E = 200 GPa. The member CD is composed of two sections placed back-to-back separated by s = 6 mm as shown. Properties of one channel A = 1774 mm2 Ix = 1.60 x 10^6 mm^4 ly = 0.13 x 10^6 mm^4 x 11.60 mm Jsing NSCP 2015 and ASD, calculate the safe value of P.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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|2.5P C PROBLEM 1 For the truss shown in SD-001, The strength of the truss is assumed to be governed by the strength of member CD. Use Fy = 248 MPa and E = 200 GPa. The member CD is composed of two sections placed back-to-back separated by s = 6 mm as shown. 30° 30° 1.5P Properties of one channel A = 1774 mm² Ix = 1.60 x 10^6 mm^4 ly = 0.13 x 10^6 mm^4 X = 11.60 mm 4 m 45° Using NSCP 2015 and ASD, calculate the safe value of P. A SD-001
Transcribed Image Text:|2.5P C PROBLEM 1 For the truss shown in SD-001, The strength of the truss is assumed to be governed by the strength of member CD. Use Fy = 248 MPa and E = 200 GPa. The member CD is composed of two sections placed back-to-back separated by s = 6 mm as shown. 30° 30° 1.5P Properties of one channel A = 1774 mm² Ix = 1.60 x 10^6 mm^4 ly = 0.13 x 10^6 mm^4 X = 11.60 mm 4 m 45° Using NSCP 2015 and ASD, calculate the safe value of P. A SD-001
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