Problem 1: One end of a spring with a spring constant of 159 N/m is held firmly in place, and the other end is attached to a block with a mass of 2.13 k The block undergoes SHO (simple harmonic motion) with no friction. At time t = 0.5963 s, the position and velocity of the block are Part (a) What was the position, in meters, at t = 0.00 s? x(0.00 s) = 1 m sin() cos() cotan() asin() atan() acotan() cosh() tanh() O Degrees Submit x(0.5963 s) = -0.08779 m v(0.5963 s) = 1.125 m/s tan() acos() E sinh() cotanh() Radians Hint Л ( 7 8 9 4 5 6 * 1 2 3 Feedback AL 1 + 0 END VO BACKSPACE DEL CLEAR 6 Part (b) What was the velocity, in meters per second, at t = 0.00 s? HOME I give up! Feedback: 0% deduction per feedback.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1: One end of a spring with a spring constant of 159 N/m is held firmly in place, and the other end is attached to a block with a mass of 2.13 kg
The block undergoes SHO (simple harmonic motion) with no friction. At time t = 0.5963 s, the position and velocity of the block are
GE
x(0.00 s) = 1
Part (a) What was the position, in meters, at t = 0.00 s?
m
sin()
cotan()
cos()
asin()
atan() acotan()
cosh()
tanh()
O Degrees
Submit
x(0.5963 s) = -0.08779 m
v (0.5963 s) = 1.125 m/s
tan() JT (
acos() E
sinh()
cotanh()
Radians
Hint
7 8
AL
/
4 5
12
0
VO BACKSPACE DEL CLEAR
+ -
END
Feedback
9 | HOME
6
3
I give up!
Feedback: 0% deduction per feedback.
Part (b) What was the velocity, in meters per second, at t = 0.00 s?
Transcribed Image Text:Problem 1: One end of a spring with a spring constant of 159 N/m is held firmly in place, and the other end is attached to a block with a mass of 2.13 kg The block undergoes SHO (simple harmonic motion) with no friction. At time t = 0.5963 s, the position and velocity of the block are GE x(0.00 s) = 1 Part (a) What was the position, in meters, at t = 0.00 s? m sin() cotan() cos() asin() atan() acotan() cosh() tanh() O Degrees Submit x(0.5963 s) = -0.08779 m v (0.5963 s) = 1.125 m/s tan() JT ( acos() E sinh() cotanh() Radians Hint 7 8 AL / 4 5 12 0 VO BACKSPACE DEL CLEAR + - END Feedback 9 | HOME 6 3 I give up! Feedback: 0% deduction per feedback. Part (b) What was the velocity, in meters per second, at t = 0.00 s?
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