Problem 1 Length Required for Cooling Coil A cooling coil made of copper tube is immersed in a regulated constant temperature bath held at a temperature of 18 °C. The liquid flowing through the tube enters at 22 °C, and the coil must be sufficiently long to ensure the exit liquid sustains a temperature of 18.5 °C. The bath is so well stirred that heat transfer resistance at the tube-bath interface is minimal, and the copper wall resistance can also be ignored. Assume Plug Flow Model is applied for fluid flow profile in a tube. Thus, the tube wall temperature can be taken equal to the bath temperature. Use Eq. 1.17 to T(z) Control volume A) Estimate the required tube length (L) under the following conditions for the flowing liquid: Where Tw z+Az T(z+Az) Nu = Since the Reynolds number is in the turbulent range, use the correlation of Sieder and Tate (Bird et al. 1960) to calculate h Nu hD k Pr = Re= = C, 1 kcal/kg.°C R = 0.01 m Vo = 1 m/s P = 10³kg/m³ μ = 0.001 kg/m.s k 1.43 10-4 kcal/(s m K) 0.026 Re0.8 Pr¹/3 DuoP μ (D = 2R), Nusselt number C₂μ Cu toat Prandtl number Reynolds number B) Discuss on the consequence of decreasing fluid velocity vo to 0.5 m/s when the other parameters are the same as given. C) Discuss on the consequence of decreasing diameter of tube to 0.01 m when the other parameters are the same as given.
Problem 1 Length Required for Cooling Coil A cooling coil made of copper tube is immersed in a regulated constant temperature bath held at a temperature of 18 °C. The liquid flowing through the tube enters at 22 °C, and the coil must be sufficiently long to ensure the exit liquid sustains a temperature of 18.5 °C. The bath is so well stirred that heat transfer resistance at the tube-bath interface is minimal, and the copper wall resistance can also be ignored. Assume Plug Flow Model is applied for fluid flow profile in a tube. Thus, the tube wall temperature can be taken equal to the bath temperature. Use Eq. 1.17 to T(z) Control volume A) Estimate the required tube length (L) under the following conditions for the flowing liquid: Where Tw z+Az T(z+Az) Nu = Since the Reynolds number is in the turbulent range, use the correlation of Sieder and Tate (Bird et al. 1960) to calculate h Nu hD k Pr = Re= = C, 1 kcal/kg.°C R = 0.01 m Vo = 1 m/s P = 10³kg/m³ μ = 0.001 kg/m.s k 1.43 10-4 kcal/(s m K) 0.026 Re0.8 Pr¹/3 DuoP μ (D = 2R), Nusselt number C₂μ Cu toat Prandtl number Reynolds number B) Discuss on the consequence of decreasing fluid velocity vo to 0.5 m/s when the other parameters are the same as given. C) Discuss on the consequence of decreasing diameter of tube to 0.01 m when the other parameters are the same as given.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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