Problem 1 Hydrogen gas is burned in an adiabatic reactor with two times the theo- retical quantity of air, both air and hydrogen being at 298 K initially. What will be the tempera- ture of the reaction products? The standard heat of formation of gaseous water is -241.826 kJ/mol. The heat capacities (kJ/kmol K) of the gases are given below: Water vapour: Nitrogen: Oxygen: Cp = 30,475 + 9.652 × 103T + 1.189 × 10-672 Cp = 27.034 + 5.815 × 103T – 0.2889 × 10 672 Cp = 25.611 + 13.260 × 103T – 4.2077 × 10-72

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Problem 1
Hydrogen gas is burned in an adiabatic reactor with two times the theo-
retical quantity of air, both air and hydrogen being at 298 K initially. What will be the tempera-
ture of the reaction products? The standard heat of formation of gaseous water is -241.826
kJ/mol. The heat capacities (kJ/kmol K) of the gases are given below:
Water vapour:
Nitrogen:
Oxygen:
Cp = 30,475 + 9.652 × 103T + 1.189 × 10-672
Cp = 27.034 + 5.815 × 103T – 0.2889 × 10 672
Cp = 25.611 + 13.260 × 103T – 4.2077 × 10-72
Transcribed Image Text:Problem 1 Hydrogen gas is burned in an adiabatic reactor with two times the theo- retical quantity of air, both air and hydrogen being at 298 K initially. What will be the tempera- ture of the reaction products? The standard heat of formation of gaseous water is -241.826 kJ/mol. The heat capacities (kJ/kmol K) of the gases are given below: Water vapour: Nitrogen: Oxygen: Cp = 30,475 + 9.652 × 103T + 1.189 × 10-672 Cp = 27.034 + 5.815 × 103T – 0.2889 × 10 672 Cp = 25.611 + 13.260 × 103T – 4.2077 × 10-72
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