PROBLEM 1 GIVEN Critical Height of Cone = Diameter of Cylinder = Angle of Cone = Bulk Density= REQUIRED SOLUTION he= D= 0= = Y= Determine the height of a tank that holds exactly 1500 cubic ft. Input Cells: Critical Height of Cone = Diameter of Cone = Angle of Cone = 7.14 ft 10 35 deg 25 pcf hc= D= 0 = Cell that Goal Seek Changes (By Changing Cell): Overall Tank Height = h= radius= Tank Volume (Set Cell)= Value that Goal Seek Is Looking For (To Value); Tank Volume = V= Cell that Goal Seek Is Checking Against: r= V= 7.14 ft 10 ft 35 deg h = ft ft Thus the final result is that the overall height of the tank is: Overall Tank Height = D-diameter of tank Figure 1. Problem 1 sketch. he Results of Goal Seek Helpful Equations: Volume of a Cone: V = ²³h Volume of a cylinder: V = n( ² ) ² (h – h)
PROBLEM 1 GIVEN Critical Height of Cone = Diameter of Cylinder = Angle of Cone = Bulk Density= REQUIRED SOLUTION he= D= 0= = Y= Determine the height of a tank that holds exactly 1500 cubic ft. Input Cells: Critical Height of Cone = Diameter of Cone = Angle of Cone = 7.14 ft 10 35 deg 25 pcf hc= D= 0 = Cell that Goal Seek Changes (By Changing Cell): Overall Tank Height = h= radius= Tank Volume (Set Cell)= Value that Goal Seek Is Looking For (To Value); Tank Volume = V= Cell that Goal Seek Is Checking Against: r= V= 7.14 ft 10 ft 35 deg h = ft ft Thus the final result is that the overall height of the tank is: Overall Tank Height = D-diameter of tank Figure 1. Problem 1 sketch. he Results of Goal Seek Helpful Equations: Volume of a Cone: V = ²³h Volume of a cylinder: V = n( ² ) ² (h – h)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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use Goal Seek to determine the overall height of the tank when the volume is exactly 1500 ft3.
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