PROBLEM 1 GIVEN Critical Height of Cone = Diameter of Cylinder = Angle of Cone = Bulk Density= REQUIRED SOLUTION he= D= 0= = Y= Determine the height of a tank that holds exactly 1500 cubic ft. Input Cells: Critical Height of Cone = Diameter of Cone = Angle of Cone = 7.14 ft 10 35 deg 25 pcf hc= D= 0 = Cell that Goal Seek Changes (By Changing Cell): Overall Tank Height = h= radius= Tank Volume (Set Cell)= Value that Goal Seek Is Looking For (To Value); Tank Volume = V= Cell that Goal Seek Is Checking Against: r= V= 7.14 ft 10 ft 35 deg h = ft ft Thus the final result is that the overall height of the tank is: Overall Tank Height = D-diameter of tank Figure 1. Problem 1 sketch. he Results of Goal Seek Helpful Equations: Volume of a Cone: V = ²³h Volume of a cylinder: V = n( ² ) ² (h – h)
PROBLEM 1 GIVEN Critical Height of Cone = Diameter of Cylinder = Angle of Cone = Bulk Density= REQUIRED SOLUTION he= D= 0= = Y= Determine the height of a tank that holds exactly 1500 cubic ft. Input Cells: Critical Height of Cone = Diameter of Cone = Angle of Cone = 7.14 ft 10 35 deg 25 pcf hc= D= 0 = Cell that Goal Seek Changes (By Changing Cell): Overall Tank Height = h= radius= Tank Volume (Set Cell)= Value that Goal Seek Is Looking For (To Value); Tank Volume = V= Cell that Goal Seek Is Checking Against: r= V= 7.14 ft 10 ft 35 deg h = ft ft Thus the final result is that the overall height of the tank is: Overall Tank Height = D-diameter of tank Figure 1. Problem 1 sketch. he Results of Goal Seek Helpful Equations: Volume of a Cone: V = ²³h Volume of a cylinder: V = n( ² ) ² (h – h)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
use Goal Seek to determine the overall height of the tank when the volume is exactly 1500 ft3.
![PROBLEM 1
GIVEN
Critical Height of Cone =
Diameter of Cylinder =
Angle of Cone =
Bulk Density=
REQUIRED
SOLUTION
hc=
D=
0 =
y =
Input Cells:
Determine the height of a tank that holds exactly 1500 cubic ft.
Critical Height of Cone =
Diameter of Cone =
Angle of Cone =
Value that Goal Seek Is Looking
ft
10 ft
35
7.14
deg
25 pcf
radius=
Tank Volume (Set Cell)=
Cell that Goal Seek Changes (By Changing Cell):
Overall Tank Height = h =
hc =
D=
0 =
Overall Tank Height =
Tank Volume = V=
Cell that Goal Seek Is Checking Against:
r=
V=
For (To Value):
ft
7.14
10 ft
35 deg
h =
ft
Thus the final result is that the overall height of the tank is:
ft
ft³
D-diameter of tank
r
Figure 1. Problem 1 sketch.
hc
Results of Goal Seek
Helpful Equations:
Volume of a Cone:
V = = = πr²³h
Volume of a cylinder:
V =
π(12/7) ² (n − n)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4d4321a5-4dfd-4eec-a3eb-8a39051ceb96%2F1155b404-0d35-4bcd-8dfa-efa0de581561%2Fch5hka_processed.png&w=3840&q=75)
Transcribed Image Text:PROBLEM 1
GIVEN
Critical Height of Cone =
Diameter of Cylinder =
Angle of Cone =
Bulk Density=
REQUIRED
SOLUTION
hc=
D=
0 =
y =
Input Cells:
Determine the height of a tank that holds exactly 1500 cubic ft.
Critical Height of Cone =
Diameter of Cone =
Angle of Cone =
Value that Goal Seek Is Looking
ft
10 ft
35
7.14
deg
25 pcf
radius=
Tank Volume (Set Cell)=
Cell that Goal Seek Changes (By Changing Cell):
Overall Tank Height = h =
hc =
D=
0 =
Overall Tank Height =
Tank Volume = V=
Cell that Goal Seek Is Checking Against:
r=
V=
For (To Value):
ft
7.14
10 ft
35 deg
h =
ft
Thus the final result is that the overall height of the tank is:
ft
ft³
D-diameter of tank
r
Figure 1. Problem 1 sketch.
hc
Results of Goal Seek
Helpful Equations:
Volume of a Cone:
V = = = πr²³h
Volume of a cylinder:
V =
π(12/7) ² (n − n)
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