Homework Help is Here – Start Your Trial Now!
Engineering
Electrical Engineering
Problem 1 - For the circuit below, determine the voltages across C₁ and C₂ and the currents through L₁, L2 and L3 under D.C. conditions. (Note: There is no switching and all conditions have been going for a while.) 2 ΚΩ L3= 1 mH m L₁ = 0.2 mH m L2 = 0.5 mH C₁ = 10 μF + 1 4 ΚΩ 6 ΚΩ C₂=4 μF 24 V

Problem 1 - For the circuit below, determine the voltages across C₁ and C₂ and the currents through L₁, L2 and L3 under D.C. conditions. (Note: There is no switching and all conditions have been going for a while.) 2 ΚΩ L3= 1 mH m L₁ = 0.2 mH m L2 = 0.5 mH C₁ = 10 μF + 1 4 ΚΩ 6 ΚΩ C₂=4 μF 24 V

Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter7: Parallel Circuits
Section: Chapter Questions
Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....
See similar textbooks
icon
Related questions
Question
**Problem 1 –** For the circuit below, determine the voltages across C₁ and C₂ and the currents through L₁, L₂, and L₃ under D.C. conditions. (**Note:** There is no switching and all conditions have been going for a while.) ### Circuit Diagram Description: - **Resistors:** - There is a 2 kΩ resistor connected in series. - There is a 6 kΩ resistor connected in series. - There is a 4 kΩ resistor connected in parallel with the capacitors and inductors. - **Inductors:** - \( L₁ = 0.2 \text{ mH} \) - \( L₂ = 0.5 \text{ mH} \) - \( L₃ = 1 \text{ mH} \) - **Capacitors:** - \( C₁ = 10 \text{ μF} \) - \( C₂ = 4 \text{ μF} \) - **Power Supply:** - A 24 V DC voltage source. ### Diagram Analysis: The circuit consists of a series and parallel combination of resistors, inductors, capacitors, and a DC voltage source. The resistances and inductances are given in kΩ and mH respectively which are higher orders of ohms and henries. - The 2 kΩ resistor is placed in series with the inductances \( L₁ \) and \( L₃ \) and another 6 kΩ resistor. - The 4 kΩ resistor is placed in parallel with the capacitor \( C₁ \) and in series with the capacitor \( C₂ \). - A 24 V power supply is connected across the entire circuit. ### Detailed Explanation: Under DC conditions (steady state) for a long time: - Inductors (L) behave as short circuits (0 Ω resistance). - Capacitors (C) behave as open circuits (infinite resistance). Given these considerations and analysis of the DC behavior: 1. **Voltage across Capacitors (C₁ and C₂):** - Capacitors in steady-state act as open circuits, meaning they will hold the voltage constant when charged. - The voltage across \( C₂ \) would be the same as the supply voltage if it's directly connected. 2. **Currents through Inductors
Transcribed Image Text:**Problem 1 –** For the circuit below, determine the voltages across C₁ and C₂ and the currents through L₁, L₂, and L₃ under D.C. conditions. (**Note:** There is no switching and all conditions have been going for a while.) ### Circuit Diagram Description: - **Resistors:** - There is a 2 kΩ resistor connected in series. - There is a 6 kΩ resistor connected in series. - There is a 4 kΩ resistor connected in parallel with the capacitors and inductors. - **Inductors:** - \( L₁ = 0.2 \text{ mH} \) - \( L₂ = 0.5 \text{ mH} \) - \( L₃ = 1 \text{ mH} \) - **Capacitors:** - \( C₁ = 10 \text{ μF} \) - \( C₂ = 4 \text{ μF} \) - **Power Supply:** - A 24 V DC voltage source. ### Diagram Analysis: The circuit consists of a series and parallel combination of resistors, inductors, capacitors, and a DC voltage source. The resistances and inductances are given in kΩ and mH respectively which are higher orders of ohms and henries. - The 2 kΩ resistor is placed in series with the inductances \( L₁ \) and \( L₃ \) and another 6 kΩ resistor. - The 4 kΩ resistor is placed in parallel with the capacitor \( C₁ \) and in series with the capacitor \( C₂ \). - A 24 V power supply is connected across the entire circuit. ### Detailed Explanation: Under DC conditions (steady state) for a long time: - Inductors (L) behave as short circuits (0 Ω resistance). - Capacitors (C) behave as open circuits (infinite resistance). Given these considerations and analysis of the DC behavior: 1. **Voltage across Capacitors (C₁ and C₂):** - Capacitors in steady-state act as open circuits, meaning they will hold the voltage constant when charged. - The voltage across \( C₂ \) would be the same as the supply voltage if it's directly connected. 2. **Currents through Inductors
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS