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Problem 1: Convert the following higher-order ODEs into a system of first ord ODEs (no need to solve the system). You will need to convert the initial conditio as well. [Note that apostrophes are shorthand for derivatives] (a) y"" + 3y" - 2y' + y = 0; y(0) = 2; y'(0) = 1; y"(0) = 3 (b) y" = sin(x); y(0) = 1; y'(0) = 0; y"(0) = 4 (c) (yy')' + y = 0; y(0) = 2; y'(0) = 1

Problem 1: Convert the following higher-order ODEs into a system of first ord ODEs (no need to solve the system). You will need to convert the initial conditio as well. [Note that apostrophes are shorthand for derivatives] (a) y"" + 3y" - 2y' + y = 0; y(0) = 2; y'(0) = 1; y"(0) = 3 (b) y" = sin(x); y(0) = 1; y'(0) = 0; y"(0) = 4 (c) (yy')' + y = 0; y(0) = 2; y'(0) = 1

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Problem 1: Convert the following higher-order ODEs into a system of first order ODES (no need to solve the system). You will need to convert the initial conditions as well. [Note that apostrophes are shorthand for derivatives] (a) y'" + 3y" - 2y' + y = 0; y(0) = 2; y'(0) = 1; y"(0) = 3 (b) y"" = sin (x); y(0) = 1; y'(0) = 0; y"(0) = 4 (c) (yy')' + y = 0; y(0) = 2; y'(0) = 1
Transcribed Image Text:Problem 1: Convert the following higher-order ODEs into a system of first order ODES (no need to solve the system). You will need to convert the initial conditions as well. [Note that apostrophes are shorthand for derivatives] (a) y'" + 3y" - 2y' + y = 0; y(0) = 2; y'(0) = 1; y"(0) = 3 (b) y"" = sin (x); y(0) = 1; y'(0) = 0; y"(0) = 4 (c) (yy')' + y = 0; y(0) = 2; y'(0) = 1
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