Problem 1 Box G has a mass of 200 kg, is hung from cable ADEFG, and is supported by cable AC and spring AB as shown. Determine the force in cable AC, the force in spring AB, and the distance spring AB stretched when box G was hung. D 135° 20°C A 40% 200 G kg wwwwwww k=500 N/cm
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![Problem 1
Box G has a mass of 200 kg, is hung from cable ADEFG, and is supported by cable AC and spring AB as shown.
Determine the force in cable AC, the force in spring AB, and the distance spring AB stretched when box G was
hung.
D
135°
20°C
A
40%
200 G
kg
wwwwwww
k=500 N/cm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6dce9d6b-f242-4d57-8d06-f25831a64397%2Fbd6d9830-759d-4cc1-83ba-85156bcda544%2Fstfl53j_processed.jpeg&w=3840&q=75)
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- Repeat Prob. 4.152 assuming that the 400-kN force is applied at O instead of L.4 A ski resort chair lift has towers spaced 38 m horizontaly appart. The upper tower is 15 m higher than the previous tower. If the chairs are 12 m horizontally appart and the first chair is 5 m past the lower tower what is the tension on both ends of the cable? 1:37:01 Book The mass of each chair is 350 Kg and the height above the lower tower for each chair's attachment to the cable is 0.58537 m, 4 m, 9.4244 m. Lower Tower Cable Tension = Upper Tower Cable Tension = kN. KN.Question 2 Find the value of The reaction force at the support A. (X,XX,XXX represents the last digits number pf your IC) 4m 400 KN 10 m B 60 KN 4m 10 m. 157KN 4m 17 m D
- A ski resort chair lift has towers spaced 44 m horizontaly appart. The upper tower is 15 m higher than the previous tower. If the chairs are 14 m horizontally appart and the first chair is 5 m past the lower tower what is the tension on both ends of the cable? The mass of each chair is 350 Kg and the height above the lower tower for each chair's attachment to the cable is 0.55624 m, 4 m, 9.33 m. Lower Tower Cable Tension = Upper Tower Cable Tension = KN. kN.Calculate the forces in members AB, BH, and BG. Members BF and CG are cables which can support tension only. Forces are positive if in tension, negative if in compression. A 5m B 5 m 54 54 Answers: AB = i BG= BH = i 8 KN H i G 16 kN c 5 m 54° 54% E D kN kN kNFor the frame shown below, The mass of the object connected is 96-kg. what is the value of the force in member BC in N? (Note: enter your numeric answer only. No need to enter units. Give your answer to three decimal places and negative for compression). FBC = -1.2 m 0.1 m 0.3 m В C 0.6 m A
- The structure consists of a spring CD and a solid member ABC with a slot at B. The peg at B fits loosely into the slot at B and can hence be interpreted as a smooth support. The unstretched length of the spring is 80 mm. 50 mm 150 mm 50 mm A D C B k = 600 N/m 1.1 Draw separate free-body diagrams of member ABC and the spring CD. 1.2 Comment on the existence of two-force members and three-force members in this system. 1.3 Determine the reactions at A and B on the member ABCCourse Home Syllabus Scores eText Study Area Document Sharing User Settings Course Tools > Problem 3.46 Each spring has an unstretched length of 2 m and a stiffness of k = 330 N/m .(Figure 1) Figure 4 m Во 12 m 6 m 1 of 1 Part A SOA = Determine the stretch in OA spring required to hold the 22-kg crate in the equilibrium position shown. Submit Express your answer to two significant figures and include the appropriate units. Part B 0 .06 P Pearson μA X Incorrect; Try Again m Previous Answers Request AnswerThe light boom AB is attached to a vertical wall by a ball and socket joint at A and supported by two cables at B. A force P is applied at B where P = 19i - 14j kN.Note that the reaction force at A acts along the boom because it is a two-force member. Calculate the magnitude of the reaction force at A in kN. %3D 2 m C 4 m 6 m y Answer: Calculato the madnitude of the tension in cable BD in kN. ere to search 3m 6m
- The grey block D in the sketch has a mass of 100 kg. The blue wedges (B and C) have a mass of 10 kg. Between A and B: usAB=0.3 Between B and C: usBC=0.2 Between C and A: μsCA=0.3 Between C and D: μsCD=0.4 Between A and D: μsAD=0.5 Determine the minimum value of force P that must be exceeded to initiate movement in block D. A B B DCalculate the forces in members AB, BH, and BG. Members BF and CG are cables which can support tension only. Forces are positive if in tension, negative if in compression. 6 kN 10 kN 5 m в 5 m c 5 m D 55 55 55° 55% H G Answers: AB i kN BH = i kN BG = i kN IICalculate the forces in members AB, BH, and BG. Members BF and CG are cables which can support tension only. Forces are positive if in tension, negative if in compression. A AB= Answers: BH = BG= 2 m 67 67/ H -4.67 8 KN -11.9 B 2 m G i 3.00e+0 17 KN c 2 m 67 67% E KN KN D KN
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