PROBLEM 1 A sample of primary standard grade K:Cr:O7 (M.M. = 294.20) weighing 0.2153 g is dissolved, the solution acidified and excess Kl added. The liberated I2 requires 44.86 mL of the NazS:Oa for titration. 1A. Complete the reduction half reaction for Cr2O72-/Cr* (3 pts) Cr2072 (aq). +. H*(aq). +. Cr**(aq). +. H20 1B. Complete the oxidation half reaction for 1M2 (3 pts) (aq). 12(aq). +. .e 1C. What is the stoichiometric mole ratio of the net redox reaction for the reaction between K2Cr207 and 12? (2 pts) mole K2Cr207 =, mole l2

PROBLEM 1 A sample of primary standard grade K:Cr:O7 (M.M. = 294.20) weighing 0.2153 g is dissolved, the solution acidified and excess Kl added. The liberated I2 requires 44.86 mL of the NazS:Oa for titration. 1A. Complete the reduction half reaction for Cr2O72-/Cr* (3 pts) Cr2072 (aq). +. H*(aq). +. Cr**(aq). +. H20 1B. Complete the oxidation half reaction for 1M2 (3 pts) (aq). 12(aq). +. .e 1C. What is the stoichiometric mole ratio of the net redox reaction for the reaction between K2Cr207 and 12? (2 pts) mole K2Cr207 =, mole l2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

A solution of HCl was titrated against sodium carbonate. What is the normality of acid for Trial 3 in the given data? T1 T2 0.3562 0.3479 0.3042 Weight (g) Initial V (mL) 0.80 1.60 0.40 Final V (mL) 35.20 36.70 39.80 Vol HCI used (ml) 35.10 39.40 N of HC (eq/L) 0.1954 0.1870 Average N of HCl (eq/L)
You want to make a solution of the primary standard sodium oxalate. It has a molecular mass of 133.999 g/mol (no error). Your analytical balance has an error of 0.2 mg. You add some weighing paper to the balance and it reads a mass of 0.23626 g. You then add sodium oxalate onto the weighing paper until the mass registers as 2.8539 g. You carefully transfer this to a 250.0 ml volumetric flask with an error of 0.1 ml and dissolve the sodium oxalate in a sufficient volume of water. What is the concentration of the oxalic acid (in M) and what is the absolute error (also in M).
A 20.330 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 74.044 g of water. A 10.245 g aliquot of this solution is then titrated with 0.1074 M HCl. It required 29.47 mL of the HCl solution to reach the methyl red endpoint. Calculate the weight percent NH, in the aqueous waste. wt% NH3 = APR 9 $ 4 R dº 10 % . 5 Search or type URL n T tv < 60 ♫ MacBook Pro A Y & N 7 907 U * 8 00 + I A ( 9 © | O - O W P J { + [ % ] delete
Oo.55. Subject :- Chemistry
TITRIMETRIC DATA SAMPLE: CANE VINEGAR % acidity in label: 4.5% %purity of KHP: 99.80% FORMULA WEIGHT of KHP: 204.22 g/mol STANDARDIZATION OF NaOH SOLUTION TRIAL 1 TRIAL 2 TRIAL 3 Weight of KHP, g 0.1012 0.1004 0.09987 Initial volume of NaOH, mL 5.00 10.01 Final volume of NaOH, mL 4.95 9.99 14.93 Molarity of NaOH Average Molarity of NaOH ANALYSIS OF ACETIC ACID IN A VINEGAR SAMPLE TRIAL 1 TRIAL 2 TRIAL 3 Volume of vinegar, mL Initial volume of NaOH, mL 1.00 1.00 1.00 14.98 22.90 30.87 Final volume of NaOH, mL 22.84 30.77 38.75 Molarity of acetic acid Average molarity of acetic acid ANALYSIS OF CARBONIC ACID IN A SODA SAMPLE TRIAL 1 TRIAL 2 TRIAL 3 Volume of soda, mL 20.0 20.0 20.0 Initial volume of NaOH, mL 20.20 22.05 23.93 Final volume of NaOH, mL 22.03 23.89 25.8 Molarity of carbonic acid Average molarity of carbonic acid
Please check if we answered thethird trial correcrtly. and show solution on how to solve. thanks
9- An aqueous solution at 25 C has a H,O concentration of 2. x 10 M. Calculate the OH concentration. Be sure your answer has 1 significant digits. || M x10 I Don't Know Submit O 2022 McGraw Hill LLC. All Rights Reserved. Tems of Use Privacy Center Accessibility 5:05 5/9/20 DELL F2 F3 F4 FS F6 F7 F8 F9 F10 F11 F12 PrtSc Insert Delete %23 & Num Lock Backspace 5 8 T CU D F K Enter く0
Titration of Vinegar Experimental Data Trial 1 Trial 2 Initial Buret Reading 0.05 mL 0.02 mL Final Buret Reading 25.25 mL 23.22 mL Volume of base used Molarity of base used 0.1045 M 0.1045 M Volume of vinegar used 5.00 mL 5.00 mL
A solution of HCl was titrated against sodium carbonate. What is the average normality of acid in the given data? (MW Na₂CO3 = 106) T2 0.3479 0.3562 0.3042 Weight (g) Initial V (ml) 0.80 1.60 35.20 36.70 39.80 Final V (mL) Vol HCl used (mL) 35.10 39.40 N of HCl (eq/L) 0.1954 0.1870 Average N of HCl (eq/L)
Note: This is an algorithm question so each attempt will have unique set of measurements. The following results were obtained when a sample of white cranberry juice was analyzed to determine its Vitamin C content. A 82.0 mL sample of the juice was placed in a flask with excess H2SO4, excess KI, and 11.00 mL of 0.07 000 M KIO3. Titration with thiosulfate solution required the use of 1.63 mL of 0.08826 M. Calculate the concentration of Vitamin C in the juice sample as mg Vit C per 100 mL juice. Here are some steps to help you work your way along the problem. All the reactions in the Background apply. • How many total millimoles of I are produced from the Reaction 4 between KI and KIO3? • How many millimoles of I are consumed in Reaction 3 with thiosulfate? . Using your previous two answers, how many millimoles of I reacted with the Vitamin C in the juice? • How many milligrams of Vitamin C were in the juice sample? • What is the concentration of Vitamin C in the juice sample expressed as…
Please show steps and answer accordingly. Thanks! *write Chemical equation first! *
8 = filled CHM-202 Lab 1 Solids and Solutions Rev 1 G6-2022 Results: 1. Models of Crystalline Unit Cells Atomic Radius (radius of styrofoam ball) Volume of one atom (one ball, 4/3r¹) Measured unit cell length (1) [1.3] No. Atoms per cell [1.3] Ratio of 1/r [1.3] Geometric unit cell length (1) [1.5a] Volume of atoms in cell [1.5c] Total 3 Volume of Unit Cell [1.5c] Percent vol filled [1.5d] Percent free space. [1.5d] I atom Simple Cubic SC 6.15mm 118 6.9 172 Raw Data (Temperature vs. Time) Trial Time CHM-202 Lab 2 Freering Point Depression Rev2 06-2022 232.6 Temp Time d= 6.9 r = 3.24 Sum v=172²³² Body Centered Cubic BCC 8 lan a atom 2.3 7.96 344 531.45 B. Cyclohexane Solutions (Trial 4 if needed) Temp Time (include units!) (include units!) Face Centered Cubic FCC (CCP) 10.8cm 4 atom 7/12 3.13 Temp 5.26 688 1259-73 Time the pieces are not Temp