Problem 1: A circular curve of 8° curvature is to be 6m wide on tangents and 0.75 m wide along the main part of the curve. The PC is at the station 5+100 and widening is to be completed at station 5+115. Determine the radius of the approach curve at the inner edge.
Problem 1: A circular curve of 8° curvature is to be 6m wide on tangents and 0.75 m wide along the main part of the curve. The PC is at the station 5+100 and widening is to be completed at station 5+115. Determine the radius of the approach curve at the inner edge.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Problem #1
![Problem 1:
A circular curve of 8° curvature is to be 6m wide on tangents and 0.75 m wide along the main
part of the curve. The PC is at the station 5+100 and widening is to be completed at station
5+115. Determine the radius of the approach curve at the inner edge.
Problem 2:
Find the radius R of the simple curve so that the curve will pass through a point which is 30 m
from the corner of the building. The center line of the curve passes through BO.
BLDG
I60
20m
Problem 3:
A simple curve of the proposed Mantabahadra Highway have a direction of tangent AB which is
due north and tangent BC bearing N 50° 00' 00" E. Point A is at P.C. whose stationing is
20+130.46. The degree of curve is 4°.
a.) Compute the stationing of point D on the curve along A line joining the center of the
curve which makes an angle of 54° with the tangent line passing thru P.C.
b.) What is the length of the line from D to the intersection of the tangent AB?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb750a45e-3da2-4a26-87ff-2a5cdaec039d%2Fad46c851-c4a8-4b65-8b4c-114652d97042%2F1xdtgwf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 1:
A circular curve of 8° curvature is to be 6m wide on tangents and 0.75 m wide along the main
part of the curve. The PC is at the station 5+100 and widening is to be completed at station
5+115. Determine the radius of the approach curve at the inner edge.
Problem 2:
Find the radius R of the simple curve so that the curve will pass through a point which is 30 m
from the corner of the building. The center line of the curve passes through BO.
BLDG
I60
20m
Problem 3:
A simple curve of the proposed Mantabahadra Highway have a direction of tangent AB which is
due north and tangent BC bearing N 50° 00' 00" E. Point A is at P.C. whose stationing is
20+130.46. The degree of curve is 4°.
a.) Compute the stationing of point D on the curve along A line joining the center of the
curve which makes an angle of 54° with the tangent line passing thru P.C.
b.) What is the length of the line from D to the intersection of the tangent AB?
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