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Problem 1: A block having a mass of m = 16 kg is suspended via two cables as shown in the figure. The angles shown in the figure are as follows: a = 15° and B = 33°. We will label the tension in Cable 1 as T and the tension in Cable 2 as T,. Cable 1 Cable 2. y m Part (a) From the images below, choose the correct free body diagram. SchematicChoice : Tiy T T12 a+B'a+B/ TI T2x mg mg mg T2 Ti T: mg mg mg Part (b) Write an expression for the sum of forces in the x direction in terms of T1, T2, m, g, a, and B. Use the specified coordinate system. Expression : ΣF -

Problem 1: A block having a mass of m = 16 kg is suspended via two cables as shown in the figure. The angles shown in the figure are as follows: a = 15° and B = 33°. We will label the tension in Cable 1 as T and the tension in Cable 2 as T,. Cable 1 Cable 2. y m Part (a) From the images below, choose the correct free body diagram. SchematicChoice : Tiy T T12 a+B'a+B/ TI T2x mg mg mg T2 Ti T: mg mg mg Part (b) Write an expression for the sum of forces in the x direction in terms of T1, T2, m, g, a, and B. Use the specified coordinate system. Expression : ΣF -

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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4.1 please answer parts b-d. other answers are answered

Problem 1: A block having a mass of m = 16 kg is suspended via two cables as shown in the figure. The angles shown in the figure are as follows: a = 15° and B = 33°. We will label the tension in Cable 1 as T, and the tension in Cable 2 as T,. Cable 1 Cable 2 → Part (a) From the images below, choose the correct free body diagram. SchematicChoice : Tiy T2 a+B'a+B T1,2 T2x mg mg mg T2 Ti T2 T2 Ti a mg mg mg Part (b) Write an expression for the sum of forces in the x direction in terms of T1, T2, m, g, a, and B. Use the specified coordinate system. Expression : EFx= Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(B), sin(a), sin(ß), tan(a), tan(ß), d, g, h, m, r, s, t, T1, T2 Part (c) Write an expression for the sum of forces in the y direction in terms of T1, T,, m, g, a, and B. Use the specified coordinate system. Expression : EFy Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(B), sin(a), sin(B), tan(a), tan(ß), d, g, h, m, r, s, t, T1, T2 Part (d) Solve for the numeric value of T, in newtons. Numeric : A numeric value is expected and not an expression. T1=. 138,4 Part (e) Solve for the numeric value of T,, in newtons. Numeric : A numeric value is expected and not an expression. T2 =. 42.71
Transcribed Image Text:Problem 1: A block having a mass of m = 16 kg is suspended via two cables as shown in the figure. The angles shown in the figure are as follows: a = 15° and B = 33°. We will label the tension in Cable 1 as T, and the tension in Cable 2 as T,. Cable 1 Cable 2 → Part (a) From the images below, choose the correct free body diagram. SchematicChoice : Tiy T2 a+B'a+B T1,2 T2x mg mg mg T2 Ti T2 T2 Ti a mg mg mg Part (b) Write an expression for the sum of forces in the x direction in terms of T1, T2, m, g, a, and B. Use the specified coordinate system. Expression : EFx= Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(B), sin(a), sin(ß), tan(a), tan(ß), d, g, h, m, r, s, t, T1, T2 Part (c) Write an expression for the sum of forces in the y direction in terms of T1, T,, m, g, a, and B. Use the specified coordinate system. Expression : EFy Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(B), sin(a), sin(B), tan(a), tan(ß), d, g, h, m, r, s, t, T1, T2 Part (d) Solve for the numeric value of T, in newtons. Numeric : A numeric value is expected and not an expression. T1=. 138,4 Part (e) Solve for the numeric value of T,, in newtons. Numeric : A numeric value is expected and not an expression. T2 =. 42.71
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