Problem 1: A 400-V, 50-Hz, 3-phase, 37.5 kW, star-connected synchronous motor has a full-load efficiency of 88%. The synchronous impedance of the motor is (0.2 +j 1.6) ohm per phase. If the excitation of the motor is adjusted to give a leading power factor of 0.9, calculate the following for full load: a) the excitation e.m.f. b) the total mechanical power developed

Introductory Circuit Analysis (13th Edition)
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Publisher:Robert L. Boylestad
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Problem 1:
A 400-V, 50-Hz, 3-phase, 37.5 kW, star-connected synchronous motor has a full-load efficiency
of 88%. The synchronous impedance of the motor is (0.2 +j 1.6) ohm per phase. If the excitation
of the motor is adjusted to give a leading power factor of 0.9, calculate the following for full load:
a) the excitation e.m.f.
b) the total mechanical power developed
Transcribed Image Text:Problem 1: A 400-V, 50-Hz, 3-phase, 37.5 kW, star-connected synchronous motor has a full-load efficiency of 88%. The synchronous impedance of the motor is (0.2 +j 1.6) ohm per phase. If the excitation of the motor is adjusted to give a leading power factor of 0.9, calculate the following for full load: a) the excitation e.m.f. b) the total mechanical power developed
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