.A bullet of mass m¡ traveling horizontally with speed u hits aProblem 1block of mass m2 (m2>>m¡) that is originally at rest and becomes embedded in the block.After the collision, the block slides horizontally a distance d on a surface with friction,and then falls off the surface at a height h as shown. The coefficient of kinetic frictionbetween the block and the surface is µg.coefficient of kinetic frictiong2m,m,ha) What is umins the minimum speed of the bullet so that the block falls off the surface?Express your answer in terms of some or all of the following: mị, m2, µks d, h and g for thegravitational constant.b) Assume that the initial speed of the bullet u is large enough for the block to fall off thesurface. Calculate x, the position where the block hits the ground measured from thebottom edge of the surface. Express your answer in terms of some or all of the following:т, тз, Мь и, а, h and g.

Answered: Image /qna-images/answer/a339fff4-ab27-4a1b-bfb7-4ec9107f6b21.jpg

Answered: Problem 1 .A bullet of mass m;…

Similar questions

Two 2.0-kg bodies, A and B, collide. The velocities before the collision are ?? = 15? ̂+ 30?̂ m/s and ?? = −10? ̂+ 5.0?̂m/s. After the collision, ?? = −5.0? ̂+ 20?̂m/s. (a) What is the final velocity of B? (b) How much kinetic energy is gained or lost in the collision?
A block with mass M = 5.70 kg is sliding in the positive x-direction at Vi = 8.45 m/s on a frictionless surface when it collides elastically in one dimension with a stationary block with mass m = 1.75 kg. Determine the velocities, Vf and vf, of the objects after the collision. Vf = m/s vf = m/s
A 4.0-kg mass, initially at rest on a horizontal frictionless surface, is struck by a 2.0-kg mass moving along the x axis with a speed of 8.0 m/s. After the collision, the 2.0-kg mass has a speed of 4.0 m/s at an angle of 37° from the positive x axis. What is the speed of the 4.0-kg mass after the collision?
A 10.0-g marble slides to the left with a velocity of magnitude 0.400 m/s on the frictionless, horizontal surface of an icy New York sidewalk and has a head-on, elastic collision with a larger 30.0-g marble sliding to the right with a velocity of magnitude 0.200 m/s. Find the velocity of each marble (magnitude and direction) after the collision. (Since the collision is head-on, all the motion is along a line.) (b) Calculate the change in momentum (that is, the momentum after the collision minus the momentum before the collision) for each marble.
A proton with an initial speed of 1.75 ✕ 108 m/s in the +x direction collides elastically with another proton initially at rest. The first proton's velocity after the collision is 1.416 ✕ 108 m/s at an angle of 36.0° with the +x-axis. What is the velocity (magnitude and direction) of the second proton after the collision? Magnitude(m/s): Direction( degree counterclockwise from the +x-axis):
On a frictionless horizontal air table, puck A (with mass 0.255 kg ) is moving toward puck B (with mass 0.370 kg ), which is initially at rest. After the collision, puck A has velocity 0.122 m/s to the left, and puck B has velocity 0.649 m/s to the right. What was the speed vAi of puck A before the collision? Calculate ΔK, the change in the total kinetic energy of the system that occurs during the collision.
Two blocks with masses 4m and 7m are on a collision course with the same initial speeds vj. The block with mass 4m is traveling to the left, and the 7m block is traveling to the right. They undergo a head-on elastic collision and each returns, along the same line as it approached. Find the final speeds of the particles. (Enter your answerss in terms of v, the initial speed of each mass.) Vamf V7mf %3D
A puck of mass mA that is moving along the +x axis with speed va collides with another puck of mass mB = 2mA. The collision is not head-on, so that after they collide, mB is located at 45◦ south of east, while mA collides head-on elastically with a stationary puck of mass mC = 3mA. If, after the second collision, the final velocity of mC is 0.450 [m/s], 25◦ north of east, what is the initial speed va?
Two objects, both with a mass of 1.91 kg are sliding across a horizontal, frictionless surface toward each other. If mass 1 has an initial velocity of 3.5 m/s i and mass 2 has an initial velocity of -2.46 m/s i, what is the change in total kinetic energy if they undergo a perfectly inelastic collision? Assume that total momentum is conserved.
Car A and Car B are traveling in the same direction (call it ), with B behind A, and initial speeds vA=5.6 m/s, and vB = 6 m/s. The cars have identical mass m=103 kg, and they experience an elastic collision. Now, this collision is observed by a third person traveling in a car with constant velocity v=6 m/s, traveling in the same direction as the two cars. From the point of view of this person calculate the following: Find the initial momentum of car a and b Find the final momentum of car a and b Find the total kinetic energy
A cue ball of mass m1 = 0.365 kg is shot at another billiard ball, with mass m2 = 0.595 kg, which is at rest. The cue ball has an initial speed of v = 5.5 m/s in the positive direction. Assume that the collision is elastic and exactly head-on. Write an expression for the horizontal component of the billiard ball's velocity, v2f, after the collision, in terms of the other variables of the problem. What is this velocity, in meters per second? Write an expression for the horizontal component of the cue ball's velocity, v1f, after the collision. What is the horizontal component of the cue ball's final velocity, in meters per second?
Two shuffleboard disks of equal mass, one orange and the other green, are involved in a perfectly elastic glancing collision. The green disk is initially at rest and is struck by the orange disk moving initially to the right at vOi = 6.55 m/s as in Figure a, shown below. After the collision, the orange disk moves in a direction that makes an angle of θ = 38.0° with the horizontal axis while the green disk makes an angle of ϕ = 52.0° with this axis as in Figure b. Determine the speed of each disk after the collision. vof = m/svgf = m/s

SEE MORE QUESTIONS