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PROBLEM 05. Refer to problem SP203. Change P=25 KN up to the left at 30 degrees w/ x-axis, Q=30 KN, W=35 KN, T=18 KN directed to the right.

PROBLEM 05. Refer to problem SP203. Change P=25 KN up to the left at 30 degrees w/ x-axis, Q=30 KN, W=35 KN, T=18 KN directed to the right.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Please refer to PROBLEM SP203 to answer PROBLEM #5.

OBLEM SP203. From the gven set of concurrent forces shown in the figure, determine the Resultant force which could represents them. P=I OKN Q=20KN Figure, 60° 3. Solubion: T=I OKN a). METHOD I (Using the components of the resultant equations), Rx =£x = P,x +Qr=Ty =10KN(cos 60° )+20KN(3/5)–10KN =7 KN Ry = £Y=- P, +Q, -W, = -10KN(sin 60° )+20KN(4/5)–30KN =- 22.66KN w=30KN %3D Ry (RF +(R,} =/(7) +(22.66) = 23.72KN 0, = tan RY 22.66 = 72.83° 7 -1 = tan downwarc to the nght, DR
Transcribed Image Text:OBLEM SP203. From the gven set of concurrent forces shown in the figure, determine the Resultant force which could represents them. P=I OKN Q=20KN Figure, 60° 3. Solubion: T=I OKN a). METHOD I (Using the components of the resultant equations), Rx =£x = P,x +Qr=Ty =10KN(cos 60° )+20KN(3/5)–10KN =7 KN Ry = £Y=- P, +Q, -W, = -10KN(sin 60° )+20KN(4/5)–30KN =- 22.66KN w=30KN %3D Ry (RF +(R,} =/(7) +(22.66) = 23.72KN 0, = tan RY 22.66 = 72.83° 7 -1 = tan downwarc to the nght, DR
PROBLEM 05. Refer to problem SP203. Change P=25 KN up to the left at 30 degrees w/ x-axis, Q=30 KN, W=35 KN, T=18 KN directed to the right.
Transcribed Image Text:PROBLEM 05. Refer to problem SP203. Change P=25 KN up to the left at 30 degrees w/ x-axis, Q=30 KN, W=35 KN, T=18 KN directed to the right.
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