In a large corporate computer network, there are an average of 27 log-ons per hour. What is theprobability that there will 10 log-ons over a 48 minute period?What is the probability that at least 5 minutes will elapse between log-ons?What would the mean length of time (in minutes) be between lob-ons?.

here given , in large corporate computer network , there are an average of 27 log-ons per hour λ…

Answered: probability that there will 10 log-ons…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

An electroencephalogram (EEG) is a tracing of brain waves recorded by an electroencephalogranh Neurologists have found that the peak EEG frequency in normal children increases with age in Ph. study (reported in Science, 1982), 287 normal children ranging from 2 to 16 years old were instructed to hold a 65-gram weight in the palm of their outstretched hand for a brief but unspecified time The peak EEG frequency (measured in hertz) was then recorded for each child. The children we grouped according to age, and the average peak frequency for each age group was recorded. The data appear in the accompanying table. AVERAGE PEAK EEG FREQUENCY AVERAGE PEAK EEG FREQUENCY AGE AGE х, уеars Y, hertz х, уears y, hertz 5.33 10 7.28 ndling. 3 5.75 11 7.06 4 5.80 12 7.60 5 5.60 13 7.45 6 6.00 14 8.23 7 5.78 15 8.50 8 5.90 16 9.38 9. 6.23 a. Construct a scattergram for the data. b. Find the least squares prediction equation. c. Graph the least squares line on the scattergram. d. Use the least squares…
The lifetime (in hours ) of a semiconductor laser has a lognormal distribution with theta = 10 and omega = 1.5 Determine the following in parts (a) and (b): a) Probability the lifetime is less than 1000 hours ? b) Probability the lifetime is less than 11000 hours given that it is more than 10000 hours?
Today, the waves are crashing onto the beach every 4.4 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 4.4 seconds. Round to 4 decimal places where possible. The probability that the wave will crash onto the beach between 1.2 and 2.1 seconds after the person arrives is P(1.2 < x < 2.1) = The probability that it will take longer than 3.28 seconds for the wave to crash onto the beach after the person arrives is P(x > 3.28) = Suppose that the person has already been standing at the shoreline for 0.7 seconds without a wave crashing in. Find the probability that it will take between 3 and 3.7 seconds for the wave to crash onto the shoreline. 62% of the time a person will wait at least how long before the wave crashes in? seconds. Find the minimum for the upper quartile. seconds. Hint:
The time, T (measured in seconds), between successive hits on a website (“inter-hit time” in the rest of the problem) follows the exponential distribution with parameter 1/2. (a) What is the probability that a randomly selected inter-hit time is between 1 and 3 seconds? (b) Assume that different inter-hit times are independent of each other. A random sample of 810 inter-hit times is obtained. Give an exact symbolic expression for the probability that more than 290 of the inter-hit times in the sample are between 1 and 3 seconds? (c) Obtain a good numerical approximation for the probability from part (b)
Today, the waves are crashing onto the beach every 5.1 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5.1 seconds. Round to 4 decimal places where possible. The probability that a person will be born between weeks 18 and 52 is P(18<x<52)P(18<x<52) = The probability that a person will be born after week 40 is P(x > 40) = P(x > 10 | x < 47) =
The time between failures of our video streaming service follows an exponential distribution with a mean of 40 days. Our servers have been running for 17 days, What is the probability that they will run for at least 97 days? (clarification: run for at least another 80 days given that they have been running 17 days). Report your answer to 3 decimal places.
The length of time (in seconds) that a user views a page on a Web site before moving to another page is a lognormal random variable with parameters 0 = 0.5 and @? = 1.96. (a) What is the probability that a page is viewed for more than 10 seconds? i (Round the answer to 4 decimal places.) (b) By what length of time have 50% of the users moved to another page? i seconds (Round the answer to 2 decimal places.) (c) What is the mean and standard deviation of the time until a user moves from the page? Mean = i seconds (Round the answer to 2 decimal places.) Standard deviation = i seconds (Round the answer to 2 decimal places.)
Question-6 The reaction time in seconds of a person can be modeled by a lognormal distributed with mean of -0.35 and standard deviation of 0.2. I. Find the probability that the reaction time is less than 0.6 seconds. II. Find the reaction time that is exceeded by 95 % of the population
The probability that an event will not happen is PE′=0.79. Find the probability that the event will happen.

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS

probability that there will 10 log-ons over a 48 minute period? What is the probability that at least 5 minutes will elapse between log-ons? What would the mean length of time (in minutes) be between lob-ons?.