probability that the second card drawnks an

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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**Probability of Drawing an Ace: A Card Probability Problem**

*Educational Exercise: Understanding Conditional Probability in Card Drawing*

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**Problem Statement:**

In a standard 52-card deck, the first card randomly drawn is an ace. If the ace is not put back into the deck, what is the probability that the second card drawn is an ace?

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**Options:**

A. 3/52  
B. 4/52  
C. 3/51  
D. 4/51  

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**Detailed Analysis:**

The right side of the image displays all 52 cards arranged in four rows, one for each suit: Hearts, Diamonds, Clubs, and Spades. Each row consists of 13 cards: Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, and King.

To solve the problem, we need to consider the following points:

1. **Total Cards Initially**: 52 cards.
2. **Aces in the Deck**: There are 4 Aces in a full deck.
3. **First Card Drawn is an Ace**: If one ace is already drawn and not replaced, there are 51 cards left in the deck.
4. **Aces Remaining After First Draw**: After drawing one Ace, 3 Aces remain in the 51 cards.

**Probability Calculation:**
- **Remaining Aces**: 3 
- **Remaining Total Cards**: 51 
- The probability of drawing one of the remaining Aces is:

\[ \frac{3}{51} = \frac{1}{17} \]

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**Answer:**

The correct answer is 

**C. 3/51**

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Transcribed Image Text:**Probability of Drawing an Ace: A Card Probability Problem** *Educational Exercise: Understanding Conditional Probability in Card Drawing* --- **Problem Statement:** In a standard 52-card deck, the first card randomly drawn is an ace. If the ace is not put back into the deck, what is the probability that the second card drawn is an ace? --- **Options:** A. 3/52 B. 4/52 C. 3/51 D. 4/51 --- **Detailed Analysis:** The right side of the image displays all 52 cards arranged in four rows, one for each suit: Hearts, Diamonds, Clubs, and Spades. Each row consists of 13 cards: Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, and King. To solve the problem, we need to consider the following points: 1. **Total Cards Initially**: 52 cards. 2. **Aces in the Deck**: There are 4 Aces in a full deck. 3. **First Card Drawn is an Ace**: If one ace is already drawn and not replaced, there are 51 cards left in the deck. 4. **Aces Remaining After First Draw**: After drawing one Ace, 3 Aces remain in the 51 cards. **Probability Calculation:** - **Remaining Aces**: 3 - **Remaining Total Cards**: 51 - The probability of drawing one of the remaining Aces is: \[ \frac{3}{51} = \frac{1}{17} \] --- **Answer:** The correct answer is **C. 3/51** ---
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