1. The population mean u is solved as follows. ΣΧ 8+12 +16 + 20+ 24 + 28 108 6. Therefore, the population mean of the tutorial rates of the select 318 teachers in Central Luzon is 18 thousand pesos per month. 2. To solve for the mean of the sampling distribution of the sample means, the following steps are to be considered. a. Identify the possible samples of size 4 and compute their individual means. Possible Sample Sample Mean 8, 12, 16, 20 14 8, 12, 16, 24 15 8, 12, 16, 28 16 8, 12, 20, 24 16 8, 12, 20, 28 17 8, 12, 24, 28 18 8, 16, 20, 24 17 18 8, 16, 20, 28 19 8, 16, 24, 28 20 8, 20, 24, 28 18 12, 16, 20, 24 19 12, 16, 20, 28 20 12, 16, 24, 28 21 12, 20, 24, 28 22 16, 20, 24, 28 EXAMPLE ONLY 93 and Probability. The following are just supplemental problems to enrich your knowledge and skills of the lesson learned. Good luck and God bless! Direction: Solve the given real - life problem below. Show the solution for the following tasks. Problem: As a Physical Education teacher of Hermosa National High School Senior High School, Ma'am Mary Ann wants to compute for the Body Mass Index of few students as part of her research. As a start, the table below shows the heights of five students in meters. Supposed samples of size 2 are taken from this population of five students, complete the given table and answer the following tasks. Construct the desired tables needed for your solutions and answers. Student Height (X) X2 Hazel Kim 1.47 2.16 Mee Ann Mae 1.58 2.50 Grace Ann 1.67 2.79 69 1.51 Jethro 2.86 Chelsea Mae 2.28 TOTAL 7.92 12.59 1. Solve for the mean of the population u. 2. Solve for the mean of the sampling distribution of the sample means H. and ug. 3. Compare H 4. Solve for the variance (o2) and the standard deviation (o) of the population. 5. Solve the variance (o2) and the standard deviation (og) of the sampling distribution of the sample means Hg. 6. Compare o and og.

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1. The population mean u is solved as follows.
ΣΧ
8+12 +16 + 20+ 24 + 28 108
6.
Therefore, the population mean of the tutorial rates of the select
318
teachers in Central Luzon is 18 thousand pesos per month.
2. To solve for the mean of the sampling distribution of the sample means,
the following steps are to be considered.
a. Identify the possible samples of size 4 and compute their
individual means.
Possible Sample
Sample Mean
8, 12, 16, 20
14
8, 12, 16, 24
15
8, 12, 16, 28
16
8, 12, 20, 24
16
8, 12, 20, 28
17
8, 12, 24, 28
18
8, 16, 20, 24
17
18
8, 16, 20, 28
19
8, 16, 24, 28
20
8, 20, 24, 28
18
12, 16, 20, 24
19
12, 16, 20, 28
20
12, 16, 24, 28
21
12, 20, 24, 28
22
16, 20, 24, 28
EXAMPLE ONLY
93
Transcribed Image Text:1. The population mean u is solved as follows. ΣΧ 8+12 +16 + 20+ 24 + 28 108 6. Therefore, the population mean of the tutorial rates of the select 318 teachers in Central Luzon is 18 thousand pesos per month. 2. To solve for the mean of the sampling distribution of the sample means, the following steps are to be considered. a. Identify the possible samples of size 4 and compute their individual means. Possible Sample Sample Mean 8, 12, 16, 20 14 8, 12, 16, 24 15 8, 12, 16, 28 16 8, 12, 20, 24 16 8, 12, 20, 28 17 8, 12, 24, 28 18 8, 16, 20, 24 17 18 8, 16, 20, 28 19 8, 16, 24, 28 20 8, 20, 24, 28 18 12, 16, 20, 24 19 12, 16, 20, 28 20 12, 16, 24, 28 21 12, 20, 24, 28 22 16, 20, 24, 28 EXAMPLE ONLY 93
and Probability.
The following are just supplemental problems to enrich your knowledge
and skills of the lesson learned. Good luck and God bless!
Direction: Solve the given real - life problem below. Show the
solution for the following tasks.
Problem: As a Physical Education teacher of Hermosa National High
School Senior High School, Ma'am Mary Ann wants to compute for the
Body Mass Index of few students as part of her research. As a start, the
table below shows the heights of five students in meters. Supposed
samples of size 2 are taken from this population of five students, complete
the given table and answer the following tasks. Construct the desired
tables needed for your solutions and answers.
Student
Height (X)
X2
Hazel Kim
1.47
2.16
Mee Ann Mae
1.58
2.50
Grace Ann
1.67
2.79
69
1.51
Jethro
2.86
Chelsea Mae
2.28
TOTAL
7.92
12.59
1. Solve for the mean of the population u.
2. Solve for the mean of the sampling distribution of the sample means H.
and ug.
3. Compare H
4. Solve for the variance (o2) and the standard deviation (o) of the population.
5. Solve the variance (o2) and the standard deviation (og) of the sampling
distribution of the sample means Hg.
6. Compare o and og.
Transcribed Image Text:and Probability. The following are just supplemental problems to enrich your knowledge and skills of the lesson learned. Good luck and God bless! Direction: Solve the given real - life problem below. Show the solution for the following tasks. Problem: As a Physical Education teacher of Hermosa National High School Senior High School, Ma'am Mary Ann wants to compute for the Body Mass Index of few students as part of her research. As a start, the table below shows the heights of five students in meters. Supposed samples of size 2 are taken from this population of five students, complete the given table and answer the following tasks. Construct the desired tables needed for your solutions and answers. Student Height (X) X2 Hazel Kim 1.47 2.16 Mee Ann Mae 1.58 2.50 Grace Ann 1.67 2.79 69 1.51 Jethro 2.86 Chelsea Mae 2.28 TOTAL 7.92 12.59 1. Solve for the mean of the population u. 2. Solve for the mean of the sampling distribution of the sample means H. and ug. 3. Compare H 4. Solve for the variance (o2) and the standard deviation (o) of the population. 5. Solve the variance (o2) and the standard deviation (og) of the sampling distribution of the sample means Hg. 6. Compare o and og.
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