Prob. 6-64

Q: Compute the combine stress on a solid round bar with a diameter of 3 cm. The load of 75,000 KN is…

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Q: A common bar suspended has an axial load of 1000 lb, it has a cross sectional area of 20 sq. in.…

A: Given data : The value of axial load P=1000 lb The value of cross sectional area A=20 in2   Required…

Q: 60 B 30

A: Draw FBD:

Q: When a bar of certain material 40 mm square is subjected to an axial pull of 1,60,000 N the…

A: From question,Axial load ,P=160000 NCross section area,

Q: A high strength steel with modulus of elasticity of A N/mm, yield strength of B N/mm and crushing…

A: Given Data:E = 239000N/mm2σy= 1300N/mm2Crushing Strength, = σc= 1740N/mm2Strain at the time of…

Q: 9. A 200 kgf load is applied to a steel bar of cross section area 6 cm². When the same load is…

A: Given data: P=200 kgf=200×9.81=1962 NAs=6 cm2=6×102 mm2εs=εAlEs=2.1×105 MN/m2=2.1×105…

Q: Determine the value of work done if force applied on crate is 12.5 N and displacement of crate is 2…

A: Introduction : The given question is related with mechanics . In this question we are provided with…

Q: 3. Convert the following: a) 650 Pa to Mpa b) 650 Pa to Kpa c) 375 kg to N

A: Given quantity; 650Pa to Mpa&Kpa 375kg to N    1MPa = 10⁶Pa Also 1Kpa = 10³Pa And, 1kg = 9.81N…

Q: Calculate the total deformation of steelbars shown in Figure. (d1=15 mm, d2=25 mm and E=210 GPa)…

A: Given  d1= 15mm d2=25mm E=210GPa = 210kN/mm2

Q: ਕਰ ਸ Elementos TAB = TBC = TBD TAD = TDC = TED= 6m 135 kN B D ( ) ) 6 m 67.5 kN 1.5 m 1.5 m 1.5 m…

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Q: 2. A man is pushing a refrigerator. The man weighs 180 lb, and the refrigerator weighs 500 lb. (a)…

A: Data given: μshoes = 0.4μrefrigerator = 0.1 Asked: At what force will the men's shoes begin to…

Q: For the beam section shown in figure, calculate the maximum load that the beam can carry without…

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Q: Determine the MAGNITUDE of the resultant F = 200 lb 888 F2 = 400 lb 888 00 888 ´F = 300 lb |F3 = 300…

A: to determine the resultant we first has to determine the incinations of forces F2 and F3let,θ=angle…

Q: fy = 415 MPa n = 9 Tension reinforcement: 2 – 25mmø RSB 1.4 Pmin fy Pmax = 0.75pp 0.85f:B, (600) Pb…

A: Given : b = 200 mm D = 400 mm, d = 337.50 mm fc = 21 MPa fy = 415 MPa

Q: How much of an increase in Fc is gained for a steel column whose end is changed from pinned-pinned…

A: When a steel column's end conditions change from pinned-pinned to fixed-fixed,Fc increases by a…

Q: Strength of Materials II HOME WORK 1- Bending For the composite beam shown in the figure below,…

A: Given:- A composite beam of steel and aluminum is given  The magnitude of the uniformly distributed…

Q: Three rods, cach of area 250 mm2. jointly support a 7.5 kN load, as shown in Figure below. Find the…

A: My dear  Given data Total hanging load Two types of materials. Area of cross section  Youngs modulus…

Q: Show full solution

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Q: What is the maximum shear?

A: Given:- To find:- Given a beam carrying different loading system. It is required to calculate…

Q: The yield limit for a type of steel material is determined to be 3600 kgs'cm². Determine the…

A: The compression strength means the material or structure's ability to resist loads that tend to…

Q: Q.9 If n is the ratio of internal and external diameter of a hollow shaft, the ratio of the weight…

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Q: 3. Determine the normal force between the crate and the surface 4. Determine the force P needed to…

A: Given- W = 856 N Frictional coefficient - μs = 0.3 height of block = h = 2 m Width of block = b = 1…

Q: Find the smallest value of P for which the 400-lb crate in the figure below will be in equilibrium…

A: The FBD of the section is given below:

Q: A common bar suspended has an axial load of 10000 lb, it has a cross sectional area of 20 sq. in.…

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Q: 120 kN/m 35 12 kNm 24 kNm 6 kNm 6 m 2 m 1 m RA Rg EMA = 0 = ??? Rg =353 kN %3D Unit of M = kNm RB =…

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Q: What is the flexural stress of a bar of chocolate that has a width of 50mm, a thickness of 0.0o09m,…

A: What is the flexural stress of a bar of chocolate?

Q: Your role as structural design engineer in a consultant firm, you have been assigned a task to…

A: As per guidelines we need to answer only first 3 subparts so please repost rest questions…

Q: 1-A load of 2 ton hanged down from a vertical round steel rod, if the stress in the rod was (1500)…

A: Note - We’ll answer the first question since the exact one wasn’t specified. Please submit a new…

Q: For a fixed-fixed nickel column with height 1.2 m, find the maximum radius to 3 significant digits…

A: To determine the maximum radius of a nickel column for given critical load,   Given, Height of…

Q: E al = 70Gpa  E cu = 75 Gpa  fınd the max stress in both of tow materials in the picture

A: The composite structure is construct of more than one material this will increase the strength and…

Q: Brinnell  hardness testing can be used for both Ferris and nonferrous metals.  The test for ferrous…

A: Answer:- Brinell Hardness Test:- This test is most commonly used to test materials that have a…

Q: Deterime the Nor mal force on crate whose mass is 28 kg resting on horizontal surface

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Q: AS DEPICTED IN THE DIAGRAM, A BEAM IS LOADED. WHAT IS THE BEAM'S EQUIVALENT CONCENTRATED LOAD? 50…

A: Given:- a loaded beam as shown below

Q: The nutural frequancy for the system is equal to

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Q: -Determine the maximum force P that can be applied without causing movement of the 90-kg crate that…

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Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.