(Prob. 2, A chain lying on the ground is 20m long and its mass is 60 kg. How much work is required to raise one end of the chain to a height of 6 m?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement:**

A chain lying on the ground is 20 meters long and its mass is 60 kilograms. How much work is required to raise one end of the chain to a height of 6 meters?

**Solution Approach:**

To solve this problem, we can use the concept of work done against gravity. The work done (W) to lift an object is calculated by the formula:

\[ W = \int_{0}^{h} F(y) \, dy \]

where \( F(y) \) is the force at a height \( y \), and \( h \) is the maximum height.

**Key Considerations:**

1. **Mass Distribution**: The mass per unit length of the chain (linear density) is calculated by dividing the total mass by the length of the chain.
   
2. **Force Calculation**: At any height \( y \), only the portion of the chain that has been lifted up to that height contributes to the gravitational force. The force \( F(y) \) at height \( y \) can be given by:

\[ F(y) = \left(\frac{\text{mass per unit length} \times y}{\text{total length}}\right) \times g \]

where \( g \) is the acceleration due to gravity.

3. **Integration**: By integrating the force over the change in height from 0 to 6 meters, we calculate the total work done.

**Conclusion:**

Performing these calculations will yield the amount of work required to raise one end of the chain to the specified height.
Transcribed Image Text:**Problem Statement:** A chain lying on the ground is 20 meters long and its mass is 60 kilograms. How much work is required to raise one end of the chain to a height of 6 meters? **Solution Approach:** To solve this problem, we can use the concept of work done against gravity. The work done (W) to lift an object is calculated by the formula: \[ W = \int_{0}^{h} F(y) \, dy \] where \( F(y) \) is the force at a height \( y \), and \( h \) is the maximum height. **Key Considerations:** 1. **Mass Distribution**: The mass per unit length of the chain (linear density) is calculated by dividing the total mass by the length of the chain. 2. **Force Calculation**: At any height \( y \), only the portion of the chain that has been lifted up to that height contributes to the gravitational force. The force \( F(y) \) at height \( y \) can be given by: \[ F(y) = \left(\frac{\text{mass per unit length} \times y}{\text{total length}}\right) \times g \] where \( g \) is the acceleration due to gravity. 3. **Integration**: By integrating the force over the change in height from 0 to 6 meters, we calculate the total work done. **Conclusion:** Performing these calculations will yield the amount of work required to raise one end of the chain to the specified height.
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