Prob-8 There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that plant X is always idling. Event B is that at least two plants generate electricity. Likelihood of the outcomes that Plant X always produce electricity is 44%. If P(AUB)' = 3%, and the likelihood of the outcomes in event A are equally likely, compute the probability of the event B? Solution: P(AUB) = P(A) + P(B) − P(AB) XYZ 000 010 001 011 XYZ 100 101 110 111
Prob-8 There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that plant X is always idling. Event B is that at least two plants generate electricity. Likelihood of the outcomes that Plant X always produce electricity is 44%. If P(AUB)' = 3%, and the likelihood of the outcomes in event A are equally likely, compute the probability of the event B? Solution: P(AUB) = P(A) + P(B) − P(AB) XYZ 000 010 001 011 XYZ 100 101 110 111
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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