//print freqs for(j=0; j
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
I need to tranform this file from C to C++
![//print freqs
for(j=0; j<size; j+){
if(freq[j]!=0}{
printf("%c' is repeated %d times. \n\n", list[j],freqli]);
}
}
return;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc45a61cd-259f-4034-96ab-adfb5c1cf9d8%2F1195567d-724d-4229-aaac-904a79699ecb%2F350htj_processed.png&w=3840&q=75)
Transcribed Image Text://print freqs
for(j=0; j<size; j+){
if(freq[j]!=0}{
printf("%c' is repeated %d times. \n\n", list[j],freqli]);
}
}
return;
![/sort datafile1 frequency
Hinclude <stdio.h>
#include <stdlib.h>
include <string.h>
*function prints frequency of list*/
void freqCount(char list[], int size){
int freq[size];
int count, j, i = 0;
for(i=0; i<size; i++){
freq[i)= -1;
//count frequencies
for(j=0; j<size; j++){
//count each number at least once
count = 1;
for(i=j+1; i<size; i++}{
//compare values
if(list[j] == list[i]}{
count++;
//if repeated set repeated numbers' freq to 0
freq[i]=0;
}
}
//store each frequency once
/if freq[j]!=0 then that number hasn't been recorded yet
if(freq[j] != 0}{
freqlj]=count;
}
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc45a61cd-259f-4034-96ab-adfb5c1cf9d8%2F1195567d-724d-4229-aaac-904a79699ecb%2F0nemxlp_processed.png&w=3840&q=75)
Transcribed Image Text:/sort datafile1 frequency
Hinclude <stdio.h>
#include <stdlib.h>
include <string.h>
*function prints frequency of list*/
void freqCount(char list[], int size){
int freq[size];
int count, j, i = 0;
for(i=0; i<size; i++){
freq[i)= -1;
//count frequencies
for(j=0; j<size; j++){
//count each number at least once
count = 1;
for(i=j+1; i<size; i++}{
//compare values
if(list[j] == list[i]}{
count++;
//if repeated set repeated numbers' freq to 0
freq[i]=0;
}
}
//store each frequency once
/if freq[j]!=0 then that number hasn't been recorded yet
if(freq[j] != 0}{
freqlj]=count;
}
}
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