Previously, an organization reported thatteenagers spent 4.5 hours per week, onaverage, on the phone. The organizationthinks that, currently, the mean is higher.Fifteen (15) randomly chosen teenagerswere asked how many hours per week theyspend on the phone. The sample mean was4.75 hours with a sample standard deviationof 2.0. What are the null and alternativehypotheses?Select the correct response:Ho: u = 4.5 Ha: > 4.5Ho μ 4.5 Ha: μ < 4.5Ho: µ = 4.75 Ha: u > 4.75Ho: x = 4.5, Ha: x > 4.5< PreviousContinue >

Here, Claim: Teenagers spent higher than 4.5 hours per week,on average,on the…

Answered: Previously, an organization reported…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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It currently takes users a mean of 12 minutes to install the most popular computer program made by RodeTech, a software design company. After changes have been made to the program, the company executives want to know if the new mean is now different from 12 minutes so that they can change their advertising accordingly. A simple random sample of 91 new customers are asked to time how long it takes for them to install the software. The sample mean is 11.7 minutes with a standard deviation of 1.6 minutes. Perform a hypothesis test at the 0.05 level of significance to see if the mean installation time has changed. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places.
NebNas manages the credit department for a grocery store chain in the province, and she would like to determine whether the mean monthly balance of credit card holders is equal to $95. A random sample of 100 accounts indicated that the mean owed is $101.5 with a sample standard deviation of $25.6. If she wanted to test whether the mean balance is different from $95 and decided to reject the null hypothesis, what will be the p-value of the test?
A quiz related to digital knowledge was conducted. The quiz had 10 questions and covered topics such as the purpose of browser cookies, phishing scams, and privacy policies. The survey was given to 50 people. The mean score is 4.1 with a standard deviation of 2.6. We want to know if the data provide evidence that the mean score in the population is lower than 5. We will use alpha = 0.05 to make our decision. What is the null hypothesis for this question? Group of answer choices a. The proportion of people who pass the test is 5. b. The mean test score of the population is 5. c. The mean test score of the 50 people who took the test is 5. d.The standard deviation is 2.6
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The College Board reports that the scores on the math SAT were normally distributed with a mean of 525. A random sample of 15 students at your high school had a mean of 550 and a sample standard deviation of 105. What values of the sample mean would lead to rejection of the null hypothesis at the 0.01 level of significance?
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City is more than the national average, a researcher decides to do a hypothesis test, at a 1% significance level. She surveys 23 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 3.8 hours per week, and the sample standard deviation (s) is 1.1 hours. H0: μ≤3; Ha: μ>3. α=0.01 (significance level) What is the test statistic (t-value) of this one-mean hypothesis test (with σ unknown)? Round your final answer to two decimal places. Provide your answer below: $$Test Statistic =
Previously, an organization reported that teenagers spent 4.5 hours per week, onaverage, on the phone. The organization thinks that, currently, the mean is higher. Fifteenrandomly chosen teenagers were asked how many hours per week they spend on thephone. The sample mean was 4.75 hours with a sample standard deviation of 2.0.At a significance level of a = 0.05, what is the correct conclusion?a. There is enough evidence to conclude that the mean number of hours is more than 4.75b. There is enough evidence to conclude that the mean number of hours is more than 4.5c. There is not enough evidence to conclude that the mean number of hours is more than4.5d. There is not enough evidence to conclude that the mean number of hours is more than4.75
It currently takes users a mean of 26 minutes to install the most popular computer program made by RodeTech, a software design company. After changes have been made to the program, the company executives want to know if the new mean is now different from 26 minutes so that they can change their advertising accordingly. A simple random sample of 37 new customers are asked to time how long it takes for them to install the software. The sample mean is 27.9 minutes with a standard deviation of 7.7 minutes. Perform a hypothesis test at the 0.05 level of significance to see if the mean installation time has changed. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
Jess2.4 employees leaving per month, with a standard deviation of 0.5. She decided to see if using a new benefits package would affect her average. She used the new benefits package for 13 months. For those 13 months, Jessica got an average of 2.6 employees leaving. She wants to know if the new benefits package caused her to get a different number of employees leaving per month. She conducts a one-mean hypothesis at the 5% significance level, to see if the new benefits package caused her to get a different number of employees leaving per month. Which answer choice shows the correct null and alternative hypotheses for this test? Select the correct answer below: H0:μ=2.4; Ha:μ≠2.4, which is a two-tailed test. H0:μ=2.4; Ha:μ<2.4, which is a left-tailed test. H0:μ=2.4; Ha:μ>2.4, which is a right-tailed test. H0:μ=2.6; Ha:μ≠2.6, which is a left-tailed test.

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