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Present an acceptable step-by-step reaction mechanism (including stereochemistry) that is consistent with the observed results.

Present an acceptable step-by-step reaction mechanism (including stereochemistry) that is consistent with the observed results.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Present an acceptable step-by-step reaction mechanism (including stereochemistry) that is consistent with the observed results.

Data Tables Table 1 -Results from experiment Mass of Alkene Mass of Product hinn nit Percent Yield Based on Limiting Reactant (Show calculations in the space below) Melting Point of Product enoitesup dal-t201 .1499 •1289 41.56% 176.3°C -180.6°C 20 J881.8H trigis zolomill M no em
Transcribed Image Text:Data Tables Table 1 -Results from experiment Mass of Alkene Mass of Product hinn nit Percent Yield Based on Limiting Reactant (Show calculations in the space below) Melting Point of Product enoitesup dal-t201 .1499 •1289 41.56% 176.3°C -180.6°C 20 J881.8H trigis zolomill M no em
Molecular Weight Milligrams Millimoles Concentration Volume Trans-cinnamic acid 148.1586 g/mol 159.808 (149x1000) = 149mg •128 x1000 = 149. 128 1.006 = 148. 1586 mmol 159.808 n/a Bromine in acetic acid g/mal n/a Equivalents 1.006.801.125 •801 Imey 2 1 = .801 128mg bodonge our /02.55 mg an DC. 1 M mmol om 10 dan M 2,3-dibromo-hydrocinnamic acid = .801 mL 307.97 g/mol 333 x 307.97= 801.4156)=333 •333 .801 n/a pla =.42
Transcribed Image Text:Molecular Weight Milligrams Millimoles Concentration Volume Trans-cinnamic acid 148.1586 g/mol 159.808 (149x1000) = 149mg •128 x1000 = 149. 128 1.006 = 148. 1586 mmol 159.808 n/a Bromine in acetic acid g/mal n/a Equivalents 1.006.801.125 •801 Imey 2 1 = .801 128mg bodonge our /02.55 mg an DC. 1 M mmol om 10 dan M 2,3-dibromo-hydrocinnamic acid = .801 mL 307.97 g/mol 333 x 307.97= 801.4156)=333 •333 .801 n/a pla =.42
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