Prepare the following solutions: 17. 50 mL of 2% ferric chloride from a 10% solution 18. 500 mL of 60% alcohol from an 80% solution 19. 950 mL of 70% alcohol from a 95% solution 20. How much water would you add to 100 mL of a 20% solution of formalin to obtain a 10% solution?
Prepare the following solutions: 17. 50 mL of 2% ferric chloride from a 10% solution 18. 500 mL of 60% alcohol from an 80% solution 19. 950 mL of 70% alcohol from a 95% solution 20. How much water would you add to 100 mL of a 20% solution of formalin to obtain a 10% solution?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![ite amount of solution from 95%
may
water anc the alcohol must be measured.
alcohol solition of an exact percentage concentration, both the
percentag but this is not a problem in routine use. To make an
up to 95 mL with water, or 700 mL of 95% alcohol up to 950
additive, the solutions will be slightly less than the indicated
mL. Because alcohol and water mix in a way that is not exactly
percentage if diluting to 950 mL. For example, a 70% alcohol
solution may be prepared by diluting 70 mL of 95% alcohol
alcohol, but for routine stock solutions it is easier to dilute to
95% or 950 mL. This is because the percentage desired may be
changed directly into milliliters if diluting to 95 mL, or 10x the
given previously
if
Am
SC
Problems
Prepare the following solutions:
Prob
Prepa
22
17. 50 mL of 2% ferric chloride from a 10% solution
18. 500 mL of 60% alcohol from an 80% solution
19.950 mL of 70% alcohol from a 95% solution
would
add to 100 mL of a 20%
20. How much water
solution of formalin to obtain a 10% solution?
you
Super problem
21. Prepare 1,000 mL of a 1:5,000 solution of light
green.
in solution](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa735a060-1a52-4418-9bd9-3dde18ad962a%2F08e959f3-233f-4472-bd53-56418bfba5d6%2Fr8lqqj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ite amount of solution from 95%
may
water anc the alcohol must be measured.
alcohol solition of an exact percentage concentration, both the
percentag but this is not a problem in routine use. To make an
up to 95 mL with water, or 700 mL of 95% alcohol up to 950
additive, the solutions will be slightly less than the indicated
mL. Because alcohol and water mix in a way that is not exactly
percentage if diluting to 950 mL. For example, a 70% alcohol
solution may be prepared by diluting 70 mL of 95% alcohol
alcohol, but for routine stock solutions it is easier to dilute to
95% or 950 mL. This is because the percentage desired may be
changed directly into milliliters if diluting to 95 mL, or 10x the
given previously
if
Am
SC
Problems
Prepare the following solutions:
Prob
Prepa
22
17. 50 mL of 2% ferric chloride from a 10% solution
18. 500 mL of 60% alcohol from an 80% solution
19.950 mL of 70% alcohol from a 95% solution
would
add to 100 mL of a 20%
20. How much water
solution of formalin to obtain a 10% solution?
you
Super problem
21. Prepare 1,000 mL of a 1:5,000 solution of light
green.
in solution
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