Predicting Relative Entropy Values PROBLEM: Choose the member with the higher entropy in each of the following pairs, and justify your choice [assume constant temperature, except in part (e)]: a) 1 mol of CO2(5) or 1 mol of CO,(g) b) 1 mol of SO2(g) or 1 mol of SO;(8) cY 3 mol of oxygen gas (O2) or 2 mol of ozone gas d) 1 mol of KBr(s) or 1 mol of KBr(aq) e) Seawater in midwinter at 2 °C or in midsummer at 23 °C f) 1 mol of CF«(g) or 1 mol of CCI4(8)

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Predicting Relative Entropy Values
PROBLEM: Choose the member with the higher entropy in each of the
following pairs, and justify your choice [assume constant temperature,
except in part (e)]:
a) 1 mol of CO2(s) or 1 mol of CO2(g)
b) 1 mol of SO2(g) or 1 mol of SO3(8)
cy 3 mol of oxygen gas (O,) or 2 mol of ozone gas
d) 1 mol of KBr(s) or 1 mol of KBr(aq)
e) Seawater in midwinter at 2 °C or in midsummer at 23 °C
f) 1 mol of CF«(g) or 1 mol of CCI4(8)
Transcribed Image Text:Predicting Relative Entropy Values PROBLEM: Choose the member with the higher entropy in each of the following pairs, and justify your choice [assume constant temperature, except in part (e)]: a) 1 mol of CO2(s) or 1 mol of CO2(g) b) 1 mol of SO2(g) or 1 mol of SO3(8) cy 3 mol of oxygen gas (O,) or 2 mol of ozone gas d) 1 mol of KBr(s) or 1 mol of KBr(aq) e) Seawater in midwinter at 2 °C or in midsummer at 23 °C f) 1 mol of CF«(g) or 1 mol of CCI4(8)
Calculate the standard entropy of reaction, ASº
Problem:
Calculate AS ° for the combustion of 1 mol of
propane at 25 °C.
C3H8(g) + 5
O2(g) = 3CO2(9) + 4H,O"
%3D
Hint: Use summation equations. It is obvious that
entropy is being lost because the reaction goes
from 6 mols of gas to 3 mols of gas.
Transcribed Image Text:Calculate the standard entropy of reaction, ASº Problem: Calculate AS ° for the combustion of 1 mol of propane at 25 °C. C3H8(g) + 5 O2(g) = 3CO2(9) + 4H,O" %3D Hint: Use summation equations. It is obvious that entropy is being lost because the reaction goes from 6 mols of gas to 3 mols of gas.
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