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Predict the product(s) for the following SN1 reaction. A (в Both I & IV Both II & III || OH₂ ||| E IV 11 OH HI III IV OH₂

Predict the product(s) for the following SN1 reaction. A (в Both I & IV Both II & III || OH₂ ||| E IV 11 OH HI III IV OH₂

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Predict the product(s) for the following Sₙ1 reaction.** The image illustrates the reaction of an alcohol with hydrogen iodide (HI) where an Sₙ1 mechanism is expected to occur. The alcohol shown at the top has a hydroxyl group (OH) on a secondary carbon of a straight-chain alkane. The potential products (I-IV) are depicted below: - **I:** A structure with a positively charged water molecule (H₂O⁺) on a secondary carbon, indicating an oxonium ion. - **II:** An isomeric structure with the iodide (I) on the secondary carbon. - **III:** A structure with iodide on the secondary carbon, similar to II, but displaying stereochemistry with a wedge bond. - **IV:** Another oxonium ion with a positively charged water molecule on the same carbon but with reversed stereochemistry compared to I. Below the structures are multiple-choice options for the predicted product(s): - **A.** Both I & IV - **B.** Both II & III - **C.** II - **D.** III - **E.** IV The correct answer is highlighted as **D. III**, indicating that III is the product of the reaction, likely due to the stability of the carbocation intermediate and the subsequent addition of iodide.
Transcribed Image Text:**Predict the product(s) for the following Sₙ1 reaction.** The image illustrates the reaction of an alcohol with hydrogen iodide (HI) where an Sₙ1 mechanism is expected to occur. The alcohol shown at the top has a hydroxyl group (OH) on a secondary carbon of a straight-chain alkane. The potential products (I-IV) are depicted below: - **I:** A structure with a positively charged water molecule (H₂O⁺) on a secondary carbon, indicating an oxonium ion. - **II:** An isomeric structure with the iodide (I) on the secondary carbon. - **III:** A structure with iodide on the secondary carbon, similar to II, but displaying stereochemistry with a wedge bond. - **IV:** Another oxonium ion with a positively charged water molecule on the same carbon but with reversed stereochemistry compared to I. Below the structures are multiple-choice options for the predicted product(s): - **A.** Both I & IV - **B.** Both II & III - **C.** II - **D.** III - **E.** IV The correct answer is highlighted as **D. III**, indicating that III is the product of the reaction, likely due to the stability of the carbocation intermediate and the subsequent addition of iodide.
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