Predict the products at the anode and the cathode obtained from electrolysis of a 1 M Znl2 solution. Note that 2 H20(1) + 2e –→ H2(g) + 2 OH¨(aq) E°red = -0.83 V O2lg) + 4 H*(aq) + 4e¯ → 2 H2O(1) E°red = +1.23 V 2(s) + 2e → 2 I(aq) Zn2*(aq) + 2e¯ → Zn(s) E°red = +0.54 V E°red = -0.76 V (Show work for full or partial credit.) The product at the anode is l2(s). The product at the cathode is Zn(s). The product at the anode is O2(g) and H*(aq). The product at the cathode is Zn(s). None of these The product at the anode is Zn(s). The product at the cathode is O2(g) and H*(aq). The product at the anode is O2(g) and H*(aq). The products at the cathode are H2(g) and OH'(aq). The products at the anode are H2(g) and OH (aq). The product at the cathode is O2(g) and H*(aq). The product at the anode is Zn(s). The product at the cathode is I2(s).
Predict the products at the anode and the cathode obtained from electrolysis of a 1 M Znl2 solution. Note that 2 H20(1) + 2e –→ H2(g) + 2 OH¨(aq) E°red = -0.83 V O2lg) + 4 H*(aq) + 4e¯ → 2 H2O(1) E°red = +1.23 V 2(s) + 2e → 2 I(aq) Zn2*(aq) + 2e¯ → Zn(s) E°red = +0.54 V E°red = -0.76 V (Show work for full or partial credit.) The product at the anode is l2(s). The product at the cathode is Zn(s). The product at the anode is O2(g) and H*(aq). The product at the cathode is Zn(s). None of these The product at the anode is Zn(s). The product at the cathode is O2(g) and H*(aq). The product at the anode is O2(g) and H*(aq). The products at the cathode are H2(g) and OH'(aq). The products at the anode are H2(g) and OH (aq). The product at the cathode is O2(g) and H*(aq). The product at the anode is Zn(s). The product at the cathode is I2(s).
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Predict the products at the anode and the cathode obtained from electrolysis of a 1 M Znl2
solution.
Note that
2 H20(1) + 2e → H2(g) + 2 OH(aq) E°red = -0.83 V
O2(g) + 4 H*(aq) + 4e¯ → 2 H20(1)
I2(s) + 2e → 2 I'(aq)
Zn2*(aq) + 2e* → Zn(s)
E°re
= +1.23 V
red
E°red = +0.54 V
E°,
-0.76 V
red =
(Show work for full or partial credit.)
The product at the anode is 12(s).
The product at the cathode is Zn(s).
The product at the anode is O2(g) and H*(aq).
The product at the cathode is Zn(s).
None of these
The product at the anode is Zn(s).
The product at the cathode is O2lg) and H*(aq).
The product at the anode is O2lg) and H*(aq).
The products at the cathode are H2(g) and OH (aq).
The products at the anode are H2(g) and OH"(aq).
The product at the cathode is O2(g) and H*(aq).
The product at the anode is Zn(s).
The product at the cathode is I2(s).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fea72fb2e-e67f-4166-bc07-808390fef734%2Ff9a11923-f0e3-4ae7-9a55-3a28dac9c083%2Fls8japd_processed.png&w=3840&q=75)
Transcribed Image Text:Predict the products at the anode and the cathode obtained from electrolysis of a 1 M Znl2
solution.
Note that
2 H20(1) + 2e → H2(g) + 2 OH(aq) E°red = -0.83 V
O2(g) + 4 H*(aq) + 4e¯ → 2 H20(1)
I2(s) + 2e → 2 I'(aq)
Zn2*(aq) + 2e* → Zn(s)
E°re
= +1.23 V
red
E°red = +0.54 V
E°,
-0.76 V
red =
(Show work for full or partial credit.)
The product at the anode is 12(s).
The product at the cathode is Zn(s).
The product at the anode is O2(g) and H*(aq).
The product at the cathode is Zn(s).
None of these
The product at the anode is Zn(s).
The product at the cathode is O2lg) and H*(aq).
The product at the anode is O2lg) and H*(aq).
The products at the cathode are H2(g) and OH (aq).
The products at the anode are H2(g) and OH"(aq).
The product at the cathode is O2(g) and H*(aq).
The product at the anode is Zn(s).
The product at the cathode is I2(s).
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